SOMEONE PLZZZ HELP, I WILL GIVE BRAINLIEST

The first thing you should do in solving a word problem is estimate what you think the answer would be.

Lelu [443]

Answer:

The answer is True.

Step-by-step explanation:

Estimate the Answer Before Solving Having a general idea of a ballpark answer .
Or the problem lets students know if their actual answer is reasonable or not.

6 0

2 years ago

there is a beaker of 3.5% acid solution and a beaker of 6% acid solution in the science lab. Mr. Larson needs 200ml of 4.5% acid

disa [49]

Below are the choices:

A. 80 mL of the 3.5% solution and 120 mL of the 6% solution

B. 120 mL of the 3.5% solution and 80 mL of the 6% solution 

C. 140 mL of the 3.5% solution and 60 mL of the 6% solution 

D. 120 mL of the 3.5% solution and 80 mL of the 6% solution

Let fraction of 3.5% in final solution be p.

p * 3.5 + (1 - p) * 6 = 4.5 

3.5p + 6 - 6p = 4.5 

2.5p = 1.5 

p = 3/5 

3/5 * 200 = 120 

Therefore the answer is B. 120 ml of 3.5% and 80 ml of 6%.

6 0

3 years ago

In the past, the average age of employees of a large corporation has been 40 years. Recently, the company has been hiring older

Viktor [21]

Answer:

$p_v =P(t_{(63)}>2.5)=0.0075$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X=45$ represent the mean height for the sample

$s=16$ represent the sample standard deviation for the sample

$n=64$ sample size

$\mu_o =40$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean age is higher than 40 years, the system of hypothesis would be:

Null hypothesis: $\mu \leq 40$

Alternative hypothesis: $\mu > 40$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{45-40}{\frac{16}{\sqrt{64}}}=2.5$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=64-1=63$

Since is a one right tailed test the p value would be:

$p_v =P(t_{(63)}>2.5)=0.0075$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.

6 0

3 years ago

Any help I don't get this like it's confusing please and thank you!!!!!!

Leya [2.2K]

The way to do this problem is by Spelling HAPPY THANKSGIVING and u put them in order by the lettter to a number.

73,15,41,41,12 16,73,15,33,10,24,17,23,50,23,3317
⬆️ ⬆️
H A P P Y T H A N K S G I V I N G

Hope This Helps

7 0

3 years ago

If the average weight of sophomore boys in Arizona is 140 pounds with a standard

yKpoI14uk [10]

Answer:

Light

Step-by-step explanation:

He is below the standard deviation limits for average or normal.

5 0

3 years ago