The synthetic division is not same as the polynomial long division.
Given:
Let's take a polynomial function f(x) = divided by x-2.
Using synthetic divison:
2 1 2 -5 -6
0 2 8 6
1 4 3 0
(x-2)(x^2+4x+3)
= (x-2)(x+3)(x+1)
Polynomial long division:
x-2) (x^2+4x+3
x^3- 2x^2
4x^2 - 5x + 6
4x^2 - 8x
3x + 6
3x - 6
0
=(x-2)(x^2+4x+3)
Learn more about the division here:
brainly.com/question/21416852
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Answer:
X=69 degree
?= 50 degree
Step-by-step explanation:
exterior angle prop so 77+X =146
X=146-77
X=69
in sencond triangle
90+40+?=180
?=180-130
?=50
'a' and 'b' are integers so they are values drawn from the set {..., -3, -2, -1, 0, 1, 2, 3, ...} basically any positive or negative whole number, and we include 0 as well. If 'a' and 'b' are forced to be positive, then there are no solutions to a*b < 1. But if we include negative values, then a*b < 1 has solutions. For example (a,b) = (-2,1) is a solution because a*b = -2*1 = -2 which is less than 1.
It turns out that (a,b) = (0,k) which plugs into a/b = 0/k = 0 which is the (a,b) pairing that leads to the largest value of ab. We can use any number k as long as k is nonzero. If 'a' were nonzero, then 'a' would have to be negative while k is positive (or vice versa) to ensure that a*b is negative, but these results would make a/b smaller than 0, thus not the largest possible value of a/b
In short, the answer to your question is 0
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