What is the volume of this rectangular prism? 4.8 cm 4.1 cm 15 cm

Consumer complaints are frequently reported to the Better Business Bureau. Industries with the most complaints to the Better Bus

kiruha [24]

Answer:

(a)

$\begin{array}{ccc}{Industry} & {Frequency} & {\%Frequency} & {Bank} & {26} & {13\%} & {Cable} & {44} & {22\%} & {Car} & {42} & {21\%}& {Cell} & {60} & {30\%} & {Collection} & {28} & {14\%} & {Total} & {200} & {100\%} \ \end{array}$

(b): Cell industry

(c) See Explanation

Step-by-step explanation:

Given (Missing from the question)

$Bank = 26$

$Cable = 44$

$Car = 42$

$Cell = 60$

$Collection = 28$

$Total = 200$

Solving (a) Show the frequency and percent frequency.

The percentage frequency is calculated by:

$\%Freq = \frac{Freq}{Total} * 100\%$

So. we have:

$\%Freq = \frac{26}{200} * 100\% = 13\%$ -- Bank

$\%Freq = \frac{44}{200} * 100\% = 22\%$ --- Cable

$\%Freq = \frac{42}{200} * 100\% = 21\%$ --- Car

$\%Freq = \frac{60}{200} * 100\% = 30\%$ --- Cell

$\%Freq = \frac{28}{200} * 100\% = 14\%$ --- Collection

The table becomes:

$\begin{array}{ccc}{Industry} & {Frequency} & {\%Frequency} & {Bank} & {26} & {13\%} & {Cable} & {44} & {22\%} & {Car} & {42} & {21\%}& {Cell} & {60} & {30\%} & {Collection} & {28} & {14\%} & {Total} & {200} & {100\%} \ \end{array}$

Solving (b): The industry with the highest complaints

From the above table, the highest frequency is 60 and this represents the number of complaints of Cell industry.

Hence, the cell industry has the highest number of complaints

Solving (c): Comment

The percentage frequency table shows that the industry with the highest number of complaints is the cell industry (at 30%) and the industry with the least is the banking industry (at 13%)

5 0

3 years ago

What's 3x+1 with explanation please

Ne4ueva [31]

Answer:

if you write it in the form y=mx+c

so

y=3x+1

it's a straight line on a graph

c= y intercept

so it's where the straight line crosses the y line which in this case is +1

m= gradient

it's basically the slope of the line

si the slope is 3

5 0

3 years ago

Lloyd's Cereal company packages cereal in 1 pound boxes (16 ounces). A sample of 16 boxes is selected at random from the product

gtnhenbr [62]

Answer:

The probability that the amount dispensed per box will have to be increased is 0.0062.

Step-by-step explanation:

Consider the provided information.

Sample of 16 boxes is selected at random.

If the mean for 1 hour is 1 pound and the standard deviation is 0.1

1 Pound = 16 ounces , then 0.1 Pound = 16/10 = 1.6 ounces

Thus: μ = 16 ounces and σ = 1.6 ounces.

Compute the test statistic $z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}$

$z=\frac{15-16}{\frac{1.6}{\sqrt{16}}}$

$z=\frac{-1}{\frac{1.6}{4}}$

$z=\frac{-1}{0.4}$

$z=-2.5$

By using the table.

P value = P(Z<-250) = 0.0062

Thus, the probability that the amount dispensed per box will have to be increased is 0.0062.

7 0

3 years ago

There was 90 runners in the first half 2/5 dropped out I the second half 2/3 dropped out how many finished the race

Liula [17]

Answer:

18.

Step-by-step explanation:

If there were 90 runners, and in the first half 2/5 of them dropped out, here's how we get those who continued the race in the second half.

1. Firstly we need to calculate how many of them dropped out:

2/5 of 90 = 90 ÷ 5 × 2

2/5 of 90 = 18 × 2

2/5 of 90 = 36

2. Now we have to take away the number of dropped-out runners from the total number of runners from the beginning of the race:

90 - 36 = 54

Now we are left with 54 runners, 2/3 of which dropped out before the finish line.

1. In order to get the number of runners that finished the race, we first need to see how many of them gave up in the second half:

2/3 of 54 = 54 ÷ 3 × 2

2/3 of 54 = 18 × 2

2/3 of 54 = 36

2. Now we just take away the number of runners that dropped out in the second half from the number on the beginning of the half:

54 - 36 = 18

18 runners finished the race.

8 0

4 years ago

Please help ASAP

yaroslaw [1]

<h3>SOLUTION:</h3>

Let the length of the room = L = 12m

width of the room = b = 8m

Height of the room = h = 4m

• Area of the four walls of the room = Perimeter of the base x Height of the room.

$= 2(l + b) \times h = 2(12 + 8) \times 4$

$= 2 \times 20 \times 4 = 160 {m}^{2}$

Cost of white washing per m² = ₹5

Hence , the total cost of white washing four walls of the room ;-

₹ ( 160 x 5 ) = ₹ 800

Area of ceiling is 12 x 8 = 96m².

Cost of white washing the ceiling.

₹ (96 x 5 ) = ₹ 480.

So , the total cost of white washing ;

₹ ( 800 + 480 ) = ₹ 1280 .

Hope this helps you :)

#Carry on learning# :) ..

8 0

2 years ago