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2 years ago

Help me please this is dew by the end of the day

Mathematics

1 answer:

german2 years ago

3 0

Answer:x = 4 1/2

19-2 1/2 x2 = 14-2 1/2 x2 = 9/2 = 4 1/2

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Anthony deposited $14,000 with a bank in a 5-year certificate of deposit yielding 6% compounded daily. Find the compound amount

Mnenie [13.5K]

Answer:

Total = 14,000 * 1 + (.06 / 365) ^365*5

Total = 14,000 * 1.0.000164383561643836^1,825

Total = 14,000 * 1.3498255274

Total = 18,897.56

Step-by-step explanation:

8 0

3 years ago

An urn contains 5 white and 10 black balls. A fair die is rolled and that number of balls is randomly chosen from the urn. What

galina1969 [7]

Answer:

Part A:

The probability that all of the balls selected are white:

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

$P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

Step-by-step explanation:

A is the event all balls are white.

D_i is the dice outcome.

Sine the die is fair:

$P(D_i)=\frac{1}{6}$ for i∈{1,2,3,4,5,6}

In case of 10 black and 5 white balls:

$P(A|D_1)=\frac{5_{C}_1}{15_{C}_1} =\frac{5}{15}=\frac{1}{3}$

$P(A|D_2)=\frac{5_{C}_2}{15_{C}_2} =\frac{10}{105}=\frac{2}{21}$

$P(A|D_3)=\frac{5_{C}_3}{15_{C}_3} =\frac{10}{455}=\frac{2}{91}$

$P(A|D_4)=\frac{5_{C}_4}{15_{C}_4} =\frac{5}{1365}=\frac{1}{273}$

$P(A|D_5)=\frac{5_{C}_5}{15_{C}_5} =\frac{1}{3003}=\frac{1}{3003}$

$P(A|D_6)=\frac{5_{C}_6}{15_{C}_6} =0$

Part A:

The probability that all of the balls selected are white:

$P(A)=\sum^6_{i=1} P(A|D_i)P(D_i)$

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

We have to find $P(D_3|A)$

The data required is calculated above:

$P(D_3|A)=\frac{P(A|D_3)P(D_3)}{P(A)}\\ P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

7 0

3 years ago

PLEASE HELP IM BEING TIMED

Zigmanuir [339]

Step-by-step explanation:

You have miscopied the second equation as it contains a third variable B when there isn't a B in the answers.

Please correct it for assistance

7 0

2 years ago

What is the answer 2c+(3c-4)=a-4

gavmur [86]

Answer:idk

Step-by-step explanation:

5 0

3 years ago

Using a formula estimate the body surface area of a person whose height is 150 cm and who weighs 80 kg.

ladessa [460]

Answer:

B. $1.83\text{ m}^2$

Step-by-step explanation:

We are asked to find the body surface area of a person whose height is 150 cm and who weighs 80 kg.

$\text{Body surface area}( m^2)=\sqrt{\frac{\text{Height (cm)}\times \text{Weight (kg)}}{3600}}$

Substitute the values:

$\text{Body surface area}( m^2)=\sqrt{\frac{150\text{ cm}\times 80\text{(kg)}}{3600}}$

$\text{Body surface area}( m^2)=\sqrt{\frac{12,000}{3600}}$

$\text{Body surface area}( m^2)=\sqrt{3.3333333}$

$\text{Body surface area}( m^2)=1.825741$

$\text{Body surface area}( m^2)=1.83$

Therefore, the body surface area of the person would be 1.83 square meters.

7 0

3 years ago