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Leni [432]
3 years ago
12

The work shown is a way to derive Tangent (x + y) = StartFraction tangent (x) + tangent (y) Over 1 minus tangent (x) tangent (y)

EndFraction
What expressions go in the derivation of the tangent sum identity in place of A, B, and C?
Cos y cos x tan y sin x

Mathematics
1 answer:
Darina [25.2K]3 years ago
4 0

Answer:

A: cos x

B: cos y

C: tan y

Step-by-step explanation:

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The terminal side of an angle in standard position passes through P(15, –8). What is the value of sin theta?
MA_775_DIABLO [31]

Check the picture below.

3 0
3 years ago
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A tube for a water slide is cylindrical.The tube is 40 yards long and has a radius of 2 yards.Determine the surface area
Svetradugi [14.3K]
SA=2pi 2 40 + 2pi 4
SA=160pi+8pi
SA=168pi
or
SA=527.787566 yards cubed
6 0
3 years ago
The function f(x) = x2 + 22x + 58 is translated 4 units to the right and 16 units up. What is the vertex form of the new functio
Amiraneli [1.4K]

Answer:

Option C is correct.

Step-by-step explanation:

The given function f(x) is:

f(x) = x^2 + 22x + 58

To find the vertex find (\frac{-b}{2a} )^2 and add and subtract it from both sides of the given function

b= 22, a= 1

Putting values:

(\frac{-b}{2a} )^2 = (\frac{-22}{2(1)})^2\\=(\frac{-22}{2})^2\\= (-11)^2\\=11^2

Adding (11)^2 on both sides

f(x) = x^2 + 22x + 58 +(11)^2 -(11)^2

f(x) = x^2+22x+(11)^2 +58-(11)^2

a^2 +2ab+b^2 = (a+b)^2 Using this formula:

f(x)=(x+11)^2+58-121

f(x)=(x+11)^2-63

The vertex of the given function is (-11,-63)

The function is translated 4 units to right and 16 units up

The vertex of new function will be:

(x+4,y+16) => (-11+4,-63+16)

=> (-7,-47)

So, the vertex of new function is  (-7,-47)

The function will be

(x+7)^2 -47

So, Option C is correct.

5 0
3 years ago
Read 2 more answers
Find the volume of each figure round to the near tenth only number 2 pls it’s 20 points
Nana76 [90]

Answer:

2094.4yds cubed

Step-by-step explanation:

V=pi*r^2*h/3

V=pi*100*20/3

V≈2094.4

6 0
4 years ago
Find the magnitude of wx for w(6 -3 6) and x(6 3 4)<br> A. 2sqrt10<br> B. 35<br> C. 4sqrt2<br> D. 32
gladu [14]

Answer:

|WX|=2\sqrt{10}

Step-by-step explanation:

To find the distance between two points in there dimensional coordinate system, we use the formula;

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}

The magnitude for  w(6 ,-3 , 6)  and x(6, 3, 4)

|WX|=\sqrt{(6-6)^2+(3--3)^2+(4-6)^2}

|WX|=\sqrt{(0)^2+(6)^2+(-2)^2}

|WX|=\sqrt{0+36+4}

|WX|=\sqrt{40}

|WX|=2\sqrt{10}

The correct choice is A.

4 0
3 years ago
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