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sveticcg [70]
3 years ago
9

n a bag of 60 candies, 36 are green and 45 have caramel in them. If the events of picking a green candy and picking a candy with

caramel are independent, what is the probability of selecting two candies where the first is green and the second has caramel? Express your answer as a fraction in simplest form.
Mathematics
1 answer:
sladkih [1.3K]3 years ago
5 0
The answer is 365/24
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Find the measure of an<br> exterior angle of a regular<br> polygon with 18 sides.
Elenna [48]

Answer:

compute its exterior angle as 360/18, which is 20 degrees

Step-by-step explanation:

8 0
3 years ago
Solve the system below by substitution. Give your answer as an ordered pair.
bearhunter [10]
Work:
2x+5(6x+23)=-13
2x+30x+115=-13
32x=-128
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y=6(-4)+23
y=-24+23
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The answer is (-4,-1)

Hopefully this helps!
6 0
3 years ago
Help me! PLEASE! help help help help help help help help help help help help!!!!!!
rjkz [21]

Sara's results probably do have a higher mean, if we take into account how William is way more willing to pay 20 dollars. Honestly, I think you got your chosen answers right! Just my opinion, as someone inexperienced.

7 0
3 years ago
Find the length of the darkened arc. leave your answer in terms of
VashaNatasha [74]

Answer:

a

Step-by-step explanation:

you can split nine into three

8 0
2 years ago
Read 2 more answers
Question 7: Which of the following statements is true?
yawa3891 [41]

Problem 7)

The answer is choice B. Only graph 2 contains an Euler circuit.

-----------------

To have a Euler circuit, each vertex must have an even number of paths connecting to it. This does not happen with graph 1 since vertex A and vertex D have an odd number of vertices (3 each). The odd vertex count makes it impossible to travel back to the starting point, while making sure to only use each edge one time only.

With graph 2, each vertex has exactly two edges attached to it. So an Euler circuit is possible here.

================================================

Problem 8)

The answer is choice B) 5

-----------------

Work Shown:

abc base 2 = (a*2^2 + b*2^1 + c*2^0) base 10

101 base 2 = (1*2^2 + 0*2^1 + 1*2^0) base 10

101 base 2 = (1*4 + 0*2 + 1*1) base 10

101 base 2 = (4 + 0 + 1) base 10

101 base 2 = 5 base 10


4 0
3 years ago
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