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2 years ago

Find the total surface area of the rectangular pyramid.

Mathematics

2 answers:

pantera1 [17]2 years ago

5 0

Answer:

I can't really understand the wording but..

Step-by-step explanation

The formula for surface area of a rectangular prism is A=2(wl+hl+hw)

so yeah enjoy freedom for the rest of the day

VashaNatasha [74]2 years ago

4 0

12 because 12 is never wrong and 12 is an amazing number

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Please help asap it will help very much

qwelly [4]

Answer:

180 cm²

Step-by-step explanation:

From inspection of the diagram, the surface area is made up of the area of 4 congruent triangles and the area of one square.

Area of a square = x² (where x is the length of one side)

⇒ area of the square = 6² = 36 cm²

Area of a triangle = 1/2 x base x height

⇒ area of one triangle = 1/2 x 6 x 12 = 36 cm²

Total surface area = 4 x area of one triangle + area of the square

= 4 x 36 + 36

= 144 + 36

= 180 cm²

5 0

2 years ago

Read 2 more answers

Solve the equation.

irakobra [83]

Answer:

Step-by-step explanation:

um my mistake there is not any snawer choices i want to answerchoices maybe post some?

3 0

2 years ago

Read 2 more answers

A number increased by 4 is the same as 19 minus 2 times the number

Lelu [443]

X + 4 = 19 -2x
3x = 15
x=5

5 is the number

5 0

2 years ago

Read 2 more answers

Use the quadratic formula to solve for the roots in the following equation. 4x 2 + 5x + 2 = 2x 2 + 7x – 1

Natali5045456 [20]

Answer:

So, The roots are $x= \frac{1+\sqrt{5}i}{2} \,\, and \,\,x= \frac{1-\sqrt{5}i}{2}$

Step-by-step explanation:

$4x^2 + 5x + 2 = 2x^2 + 7x - 1$

We need to solve the equation to find the roots using quadratic formula.

The quadratic formula is:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Rearranging the above equation:

$4x^2 -2x^2+ 5x-7x + 2+1 =0$

$2x^2 -2x + 3 =0$

Where a =2 , b=-2 and c =3 Putting values in quadratic equation and solving:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-2)\pm\sqrt{(-2)^2-4(2)(3)}}{2(2)}\\x=\frac{2\pm\sqrt{4-24}}{4}\\x=\frac{2\pm\sqrt{-20}}{4}\\\sqrt{-20} \,\,can\,\,be\,\, written\,\, as\,\, 2\sqrt{-5}\\ x=\frac{2\pm2\sqrt{-5}}{4}\\x=\frac{2+2\sqrt{-5}}{4} \,\, and \,\, x=\frac{2-2\sqrt{-5}}{4}\\x=\frac{2(1+\sqrt{-5})}{4} \,\, and \,\, x=\frac{2(1-\sqrt{-5})}{4}\\ x=\frac{1+\sqrt{-5}}{2} \,\, and \,\, x=\frac{1-\sqrt{-5}}{2}\\As \,\,we\,\, know\,\, \sqrt{-1} = i \\$

$x= \frac{1+\sqrt{5}i}{2} \,\, and \,\,x= \frac{1-\sqrt{5}i}{2}$

So, The roots are $x= \frac{1+\sqrt{5}i}{2} \,\, and \,\,x= \frac{1-\sqrt{5}i}{2}$

6 0

2 years ago

The given lengths are two sides of a right triangle. All three side lengths of the triangle are integers and together form a pyt

tangare [24]

Two possibilities:
28^2 + x^2 = 96^2
OR
28^2 + 96^2 = c^2

784 + x^2 = 9216
subtract 784 from both side
x^2 = 8432
Take the square root of both sides
x = 91.83 NOT an Integer

28^2 + 96^2 = c^2
784 + 8216 = c^2
10,000 = c^2
Take the square root of both sides
c = 100 HYPOTENUSE

6 0

2 years ago