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sergey [27]
2 years ago
15

Find the total surface area of the rectangular pyramid.

Mathematics
2 answers:
pantera1 [17]2 years ago
5 0

Answer:

I can't really understand the wording but..

Step-by-step explanation

The formula for surface area of a rectangular prism is A=2(wl+hl+hw)

so yeah enjoy freedom for the rest of the day

VashaNatasha [74]2 years ago
4 0
12 because 12 is never wrong and 12 is an amazing number
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What type of transformation is used<br> when the line y = vx is transformed<br> into y= 5x?
dedylja [7]

Answer:

It gains a slope of 5 over 1

Step-by-step explanation:

4 0
3 years ago
A farmer needs to ship 71 pumpkins to a grocery store if each crates can hold 19 pumpkins how many crates Will the farmer need ?
Lesechka [4]

Answer:

The farmer will need 7 crates.

Step-by-step explanation:

<em>It is given that there are 71 pumpkins in total.</em>

<em>And each crate holds 19 pumpkins.</em>

Let the number of crates required be<em> "n".</em>

The total number of pumpkins can be calculated by multiplying number of pumpkins in each crate with total number of crates.

Thus, the equation is

19(n) = 71

n = \frac{71}{19} = 7

Thus, the farmer needs 7 crates to hold total of 71 pumpkins.

3 0
3 years ago
Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r
ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                         P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean weight = \frac{\sum X}{n} = 21.88 ounces

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = 0.201 ounces

            n = sample of boxes = 12

            \mu = population mean weight

<em>Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.</em>

<u>So, 90% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.796 < t_1_1 < 1.796) = 0.90  {As the critical value of t at 11 degrees of

                                                  freedom are -1.796 & 1.796 with P = 5%}  

P(-1.796 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.796) = 0.90

P( -1.796 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.796 \times {\frac{s}{\sqrt{n} } } ) = 0.90

P( \bar X-1.796 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.796 \times {\frac{s}{\sqrt{n} } } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X-1.796 \times {\frac{s}{\sqrt{n} } } , \bar X+1.796 \times {\frac{s}{\sqrt{n} } } ]

                                        = [ 21.88-1.796 \times {\frac{0.201}{\sqrt{12} } } , 21.88+1.796 \times {\frac{0.201}{\sqrt{12} } } ]

                                        = [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

8 0
3 years ago
At the start of the month, Suzanne's clothing store website had 7,278 hits. At the end of the month, it had 50,165 hits. If each
anyanavicka [17]

Answer:

  • <u><em>Option A. 64,500</em></u>

Explanation:

1. First, calculate the number of hits had during the month, by difference:

  • 50,165 hits - 7,278 hits = 42,887 hits

2. Round the result to obtain an approximation = 43,000 hits

3. Multiply by the time that each lasted:

  • 43,000 hits × 1.5 min/hit = 64,500 minutes.

Hence, the answer is the option A.

3 0
3 years ago
V = Bh for h. <br> A. h = BV<br> B. h=B/V<br> C. h=V/B<br> D. h = V – B
Darina [25.2K]
C. h=V/B to solve for this you need to get the variable h by itself and since h is being multiplied to B you use the opposite operation of division by divide both sides by B. Then you have h solved for h=V/B
5 0
3 years ago
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