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Temka [501]
3 years ago
11

Umm pls help me ik how to do it but not sure on this specific one

Mathematics
1 answer:
Lapatulllka [165]3 years ago
8 0

9514 1404 393

Answer:

  -8, +9

Step-by-step explanation:

You need factors of (6)(-12) = -72 that have a sum of +1.

From your knowledge of multiplication tables, you know that 72 = 8·9. Then -72 = (-8)(9), and those two factors have a sum of +1.

  6x^2 +x -12

  = 6x^2 +9x -8x -12

  = 3x(2x +3) -4(2x +3)

  = (3x -4)(2x +3)

You might be interested in
Es of two children are 11 and 8 years.
nikdorinn [45]

Answer:

<em>In 5 years the product of their ages will be 208</em>

Step-by-step explanation:

The age of two children is 11 and 8 years.

Let's call x the number of years ahead.

We need to find when the product of their future ages is 208. The 11 years old child will be 11+x years old and the other child will be 8+x years, thus:

(11+x)(8+x)=208

Operating:

88+11x+8x+x^2=208

Simplifying:

x^2+19x-120=0

Factoring:

(x-5)(x+24)=0

Solving:

x=5, x=-24

The negative solution is not valid, thus x=5

In 5 years the product of their ages will be 208

3 0
3 years ago
V to the power of 2 =47
Brilliant_brown [7]

Answer:

v = ± \sqrt{47}

Step-by-step explanation:

Given

v² = 47 ( take the square root of both sides )

v = ± \sqrt{47} ← note plus or minus

Since \sqrt{47} × \sqrt{47} = 47

and

- \sqrt{47} × - \sqrt{47} = 47

7 0
4 years ago
Round 23.5584557678 to the nearest hundredth.
lubasha [3.4K]
The hundredth is the second number to the right of the decimal point. Also, if the number directly to the right of it is 5 or larger, you will have to round up by one.

23.558 becomes 23.56.
4 0
3 years ago
PLZ help super super fast
Komok [63]

Answer:

it's E

Step-by-step explanation:

(5x+y)²

You expand the bracket

it gives;

(5x + y)(5x+y)

Now, multiply 5x by 5x=25x²

multiply 5x by y= 5xy

multiply y by 5x=5xy

multiply y by y=y²

Bringing into an equation it gives;

25x²+5xy+5xy+y²

=25x²+10xy+y²

3 0
4 years ago
PLEASE HELP!
FinnZ [79.3K]

Answer:

Terms are 2 , 3 , 7 , 31

Step-by-step explanation:

1) given a1 = 2

an+2 = 2(an) -1

put n = 1

a1 + 2 = 2a1 -1

put value of a1 in above

you'll get a3 = 2² -1

a3 = 4-1

a3 = 3

put n = 3

a3 + 2 = 2a3 -1

a5 = 2³-1

a5 = 8-1

a5 = 7

put n = 5

a5 + 2 = 2a5 -1

a7 = 2⁵ -1

a7 = 32 -1

a7 = 31

Hope you got it.

Similarly you can find 2nd one's term t23

tn = 5*n -4

here n = 23

t23 = 5 * 23 - 4

t23 = 115 -4

t23 = 111

Hope this helps you.

8 0
3 years ago
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