Answer: C. ∠SQP and ∠TQR
Step-by-step explanation:
Since, by the given diagram,
m∠TQR = m∠SQP (vertical angles)
And, m∠TQP < m∠TQR
By adding ∠TQR on both sides,
m∠TQP + m∠TQR < m∠TQR+m∠TQR
⇒m∠TQP + m∠TQR < 2 ∠TQR
⇒ 180° < 2 m∠TQR ( Because ∠TQP and ∠TQR are linear angles)
⇒ 90° < m∠TQR
Hence ∠TQR is a obtuse angle,
⇒ ∠SQP also is a obtuse angle.
The ratio of the area of the sector (S) to the area of the entire circle (C) is equal to the ratio of the angle subtended to form the sector (As) to the angle for the whole revolution (Ac)
S / C = As / Ac
Substituting the given,
S / 36 m² = 40 degrees / 360 degrees
Solving for S gives, S = 4. Thus, the area of the sector is 4 m².
Positive because a negative and a negative will always make a positive
The GCF is 4x
4x (4x^2 - x + 6)
