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NARA [144]
2 years ago
6

Which represents the polynomial below written in standard form?

Mathematics
2 answers:
Marta_Voda [28]2 years ago
7 0

Answer:

B

Step-by-step explanation:

I took the test.

STALIN [3.7K]2 years ago
6 0

Answer:

B. 4x^3}+\frac{x^2}{2}-3x+6

Step-by-step explanation:

The polynomial is \frac{x^2}{2}-3x+4x^3}+6

To write in Standard form, the greatest exponent goes first, down to the least.

The greatest exponent is 3, so 4x^3 goes first.

4x^3}+\frac{x^2}{2}-3x+6 is what you end up with

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Help algebra 2 please
kati45 [8]

Answer:

Step-by-step explanation:

(f*g)(x) = (-5x² + 2x + 7) (x +1)

          = x* (-5x² + 2x + 7) + 1*(-5x² + 2x + 7)

          = x*(-5x²) + x*2x + x*7 - 5x² + 2x + 7

        = -5x³ + 2x² + 7x - 5x² + 2x + 7

        = - 5x³ + <u>2x² -5x²</u>   <u>+ 7x + 2x </u>+7   {Combine like terms}

       =  -5x³ - 3x² + 9x + 7

4) (f*g)(x) = (x² + 2x + 4)(x - 2)

                = x*(x² + 2x + 4) - 2*(x² + 2x + 4)

                = x*x² + x*2x + x*4 - 2*x² - 2*2x -2* 4

                = x³ + 2x² + 4x  -2x² -4x - 8

                = x³ - 8

2) Speed=\dfrac{distance}{time}\\\\\\= \dfrac{d(h)}{t(h)}\\\\= \dfrac{2\sqrt{h}}{3\sqrt{4h}}=\dfrac{2*\sqrt{h}}{3*2\sqrt{h}}\\\\\\=\dfrac{1}{3}

1)d(h) = \sqrt{16h^{4}}=\sqrt{2*2*2*2*h*h*h*h}=2*2*h*h=4h^{2}\\\\\\t(h) = 3h^{4}-3h^{3}-5h^{2}= h^{2}(3h^{2}-3h - 5))\\\\Speed=\dfrac{4h^{2}}{h^{2}(3h^{2}-3h-5)}\\\\=\dfrac{4}{3h^{2}-3h-5}

7 0
3 years ago
A tree that is 4 ft tall is growing at a rate of 1 ft each year a tree that is 12 feet tall is growing at a rate of 1/2 ft each
Andreyy89

Answer:

16 years

Step-by-step explanation:

Given data

For the first tree

let the expression for the height be

y=4+x--------------1

where y= the total height

          4= the initial height

          x= the number of years

For the second tree, the expression is

y=12+0.5x-------------2

Equate 1 and 2

4+x=12+0.5x

x-0.5x=12-4

0.5x= 8

x= 8/0.5

x=16

Hence it will take 16 years for both trees to have the same height

5 0
3 years ago
How can you find the area of an irregular polygon using area formulas?
never [62]
Try to find out distinct shapes in the polygon and use their area formulas, then add up all of the shape's areas.

4 0
3 years ago
Which statements are true about the interquartile range? Select all that apply.
PilotLPTM [1.2K]

Answer:

The true statements are:

B. Interquartile ranges are not significantly impacted by outliers

C. Lower and upper quartiles are needed to find the interquartile range

E. The data values should be listed in order before trying to find the interquartile range

Step-by-step explanation:

The interquartile range is the difference between the first and third quartiles

Steps to find the interquartile range:

  • Put the numbers in order
  • Find the median Place parentheses around the numbers before and after the median
  • Find Q1 and Q3 which are the medians of the data before and after the median of all data
  • Subtract Q1 from Q3 to find the interquartile range

The interquartile range is not sensitive to outliers

Now let us find the true statements

A. Subtract the lowest and highest values to find the interquartile range ⇒ NOT true (<em>because the interquartial range is the difference between the lower and upper quartiles</em>)

B. Interquartile ranges are not significantly impacted by outliers ⇒ True <em>(because it does not depends on the smallest and largest data)</em>

<em />

C. Lower and upper quartiles are needed to find the interquartile range ⇒ True <em>(because IQR = Q3 - Q2)</em>

<em />

D. A small interquartile range means the data is spread far away from the median ⇒ NOT true (<em>because a small interquartile means data is not spread far away from the median</em>)

E. The data values should be listed in order before trying to find the interquartile range  ⇒ True <em>(because we can find the interquartial range by finding the values of the upper and lower quartiles)</em>

4 0
3 years ago
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No, the answer is D) 45.2%
4 0
3 years ago
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