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alex41 [277]
2 years ago
9

As you want. She bought 10 ounces of spicy popcorn for $2.50. When writing your answer write it as a whole number or a decimal.

A) How much does popcorn cost per ounce? The cost per ounce is dollars. B) How much popcorn can you buy per dollar? You can buy ounces of popcorn per dollar. C) Write two different equations that represent this situation. Use pp for ounces of popcorn and cc for cost in dollars. The first equation is and the second equation is
Mathematics
1 answer:
Gennadij [26K]2 years ago
6 0

Answer:

A. $0.25 per ounce

B. 4 ounces per dollar

Step-by-step explanation:

As you want. She bought 10 ounces of spicy popcorn for $2.50. When writing your answer write it as a whole number or a decimal.

A) How much does popcorn cost per ounce? The cost per ounce is dollars.

10 ounces of spicy popcorn = $2.50

1 ounce of spicy popcorn = x

Cross Multiply

10 ounces × x = $2.50

x = $2.50/10 ounces

x = $0.25 per ounce

B) How much popcorn can you buy per dollar? You can buy ounces of popcorn per dollar.

$2.50 = 10 ounces of spicy popcorn

$1 = x ounce of spicy popcorn

Cross Multiply

$2.50 × x = 10

x = 10/2.50

x = 4 ounces per dollar

C) Write two different equations that represent this situation. Use pp for ounces of popcorn and cc for cost in dollars. The first equation is and the second equation is

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Answer:

x=-2.5

Step-by-step explanation:

4x+(7-3)5=10

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A theater has a seating capacity of 750 and charges $3 for children, s5 for students, and $7 for adults. At a certain screening
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Answer:

Between 150 and 450

Step-by-step explanation:

We are going to find the number by resolving  a system of linear equations.

First we write the system equations :

C+S+A=750

Where C : children, S : students and A : adults

The equation represents the ''full attendance''

The second equation :

3C+5S+7A=3450

This equation represents the totaled receipts.

The system :

C+S+A=750\\3C+5S+7A=3450

has the following associated matrix :

\left[\begin{array}{cccc}1&1&1&750\\3&5&7&3450\end{array}\right]

By performing elementary matrix operations we find that the matrix is equivalent to

\left[\begin{array}{cccc}1&0&-1&150\\0&1&2&600\\\end{array}\right]

The new system :

C-A=150\\S+2A=600

Working with the equations :

C = 150 + A\\S = 600-2A

Our solution vector is :

\left[\begin{array}{c}C&S&A\end{array}\right] =\left[\begin{array}{c}150+A&600-2A&A\end{array}\right]

For example :

If 0 adults attended ⇒ A = 0

C = 150 + 0 \\C = 150\\S = 600 - 2A\\S = 600

This verify the totaled receipts equation :

150($3)+600($5) = $ 3450

A ≥ 0 ⇒ If A = 0 ⇒ C = 150

C = 150 is the minimum children attendance

From the equation :

S = 600 -2A

S ≥0

600 - 2A ≥ 0

600 ≥ 2A

300≥ A

A is restricted to the interval [ 0, 300]

When A = 0 ⇒ C = 150

When A = 300 ⇒C = 150 + A = 150 + 300 = 450

Children ∈ [ 150,450]

With C being an integer number (including 0)

Also S and A are integer numbers (including 0)

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