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3 years ago

Samuel is buying a pair of boots with an original price of $80.

Mathematics

2 answers:

melisa1 [442]3 years ago

8 0

Answer:

The boots would be 60 at store A and be 70 at store B

Step-by-step explanation:

So 10$ difference from store b to store a

telo118 [61]3 years ago

4 0

Both statements are true, but the better deal would be Store A if that’s what you are asking. The boots would be 60 at Store A and they would be 70 at Store B hope this helps!

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Determine if the equations are parallel perpendicular or neither 10x-2y=16 and x+5y=-20

Inessa [10]

Answer:

perpendicular lines

Step-by-step explanation:

First, put both equations into slope-intercept form.

Lets start with 10x - 2y = 16

Remember that the slope intercept formula is y = mx + b

So, we must get y alone on one side.

First, subtract 10x from both sides

10x - 2y = 16

-2y = -10x + 16

Now, divide both sides by negative 2

y = 5x - 8

Now for our second equation.

First we must subtract x from both sides

x + 5y = -20

5y = -x - 20

Now, divide both sides by 5

y = -1/5x - 4

Now, both of our equations are in slope-intercept form

Here's how to determine if two equations are parallel or perpendicular

<em>Remember that the m in y = mx + b is our slope</em>

Parallel = same slope

Perpendicular = negative reciprocal slope

(ex: take the number 6 take the number -3

negative reciprocal = -1/6 negative reciprocal = 1/3)

If we look at the slopes in both of our equations, we see that there is a negative reciprocal slope (the slopes are 5 and -1/5)

So, these two lines are perpendicular. :)

3 0

3 years ago

Help please geometry

jarptica [38.1K]

MP and MN that's angle M

answer
m<M

7 0

3 years ago

the units digit of a two-digit number is twice the tens digit. If the digits are reversed, the new number is 9 less than the ori

Anton [14]

Answer:

Step-by-step explanation:

Here is the correct and complete question: The units digit of a two-digit number is twice the tens digit. If the digits are reversed, the new number is 9 less than twice the original number. What is the original number?

Lets assume the original number be"10y+x". (x is unit digit and y is 10th digit)

∴ if number is reversed then resulting number be "10x+y".

As given: x= 2y

and $10x+y= 2(10y+x)-9$

Now, solving the equation to get original number.

$10x+y= 2(10y+x)-9$

Distributing 2 to 10y and x, then opening the parenthesis.

⇒ $10x+y= 20y+2x-9$

subtracting by (2x+y) on both side.

⇒ $8x= 19y-9$

subtituting the value of "x", which is equal to 2y.

∴ $8\times 2y= 19y-9$

⇒ $16y=19y-9$

subtracting both side by (16y-9)

⇒ $3y= 9$

cross multiplying

We get, $y= 3$

y=3

∵x= 2y

$x=2\times 3= 6$

∴ x= 6

Therefore, the original number will be 36 as x is the unit number and y as tenth number.

6 0

3 years ago

What is this 1/4 - (-3/4)= in math

Blababa [14]

Answer:

4/4 = 1

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The function h(t) = -16t^2 + 16t represents the height (in feet) of a horse (t) seconds after it jumps during a steeplechase.

Vladimir79 [104]

A.) To find the maximum height, we can take the derivative of h(t). This will give us the rate at which the horse jumps (velocity) at time t.

h'(t) = -32t + 16

When the horse reaches its maximum height, its position on h(t) will be at the top of the parabola. The slope at this point will be zero because the line tangent to the peak of a parabola is a horizontal line. By setting h'(t) equal to 0, we can find the critical numbers which will be the maximum and minimum t values.

-32t + 16 = 0

-32t = -16

t = 0.5 seconds

b.) To find out if the horse can clear a fence that is 3.5 feet tall, we can plug 0.5 in for t in h(t) and solve for the maximum height.

h(0.5) = -16(0.5)^2 + 16(-0.5) = 4 feet

If 4 is the maximum height the horse can jump, then yes, it can clear a 3.5 foot tall fence.

c.) We know that the horse is in the air whenever h(t) is greater than 0.

-16t^2 + 16t = 0

-16t(t-1)=0

t = 0 and 1

So if the horse is on the ground at t = 0 and t = 1, then we know it was in the air for 1 second.

7 0

3 years ago