Hi there!
I will help you by telling you how to solve them. I will show you one of the ways to solve this.
The first way you can solve this is by multiplying and then reducing the fraction. To do this all you need to do is multiply the numerators together and then you multiply the denominators together, after you do this you simply reduce the fraction to it's lowest possible numerator and denominator. For example:
Then to reduce:
÷ 
= 
÷ 
= 
Hope this helps!
Your friend, ASIAX
Answer: the answer is 0.679
Step-by-step explanation:
Step-by-step explanation:
4. not enough information
5.SAS
.we have PE congruent to ER
.angle PEF congruent to angle FER
.and EF that is common for both of triangles
6.SSS
.MO congruent to KL
.MK congruent to OL
.KO that is common for both of triangles.
48 stamps because 29-5=24 , 24x2=48
You have to check which of the following expressions is the rational exponent expression of third root of 4n, or mathematically, ![\sqrt[3]{4n} .](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B4n%7D%20.%20)
Consider all cases:
A. ![(4n)^3=4^3\cdot n^3=64n^3\neq\sqrt[3]{4n} .](https://tex.z-dn.net/?f=%20%284n%29%5E3%3D4%5E3%5Ccdot%20n%5E3%3D64n%5E3%5Cneq%5Csqrt%5B3%5D%7B4n%7D%20.%20%20)
B. ![3n^4\neq \sqrt[3]{4n} .](https://tex.z-dn.net/?f=%203n%5E4%5Cneq%20%5Csqrt%5B3%5D%7B4n%7D%20.%20%20)
C. quantity of 4n to the one third power is ![(4n)^{\frac{1}{3} }=\sqrt[3]{4n}](https://tex.z-dn.net/?f=%20%284n%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%3D%5Csqrt%5B3%5D%7B4n%7D%20)
(by the definition of rational power).
D. 4 times n to the one third power is ![4\cdot n^{\frac{1}{3} }=4\sqrt[3]{n}\neq \sqrt[3]{4n} .](https://tex.z-dn.net/?f=%204%5Ccdot%20n%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%3D4%5Csqrt%5B3%5D%7Bn%7D%5Cneq%20%5Csqrt%5B3%5D%7B4n%7D%20.%20%20)
Answer: correct choice is C.
