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artcher [175]
4 years ago
11

Can somebody help me with this problem

Mathematics
1 answer:
soldier1979 [14.2K]4 years ago
4 0
115 degrees because there are 180 degrees in a triangle so let the missing angle in the trinagle be x. Then we have x+75+40=180. Solving for x and subtracting that from 180 (supplementary angles) we get 115 degrees.
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25m/s to miles/h <br>Can anyone solve it?<br>With explanation if you can
Dimas [21]

25 meters per second x 60 seconds = 1500 meters per minute

1500 meters per minute x 60 minutes per hour = 90,000 meters per hour

1 mile = 1609.34 meters

90000/1609.34 = 55.92 miles per hour

 round answer to either 55.9 or 56 mph depending on what you need.

6 0
3 years ago
(2/5) x ( - 5/4) Can someone please help me
anastassius [24]
The answer would be -10/20 which is simplified to -1/2
5 0
3 years ago
Read 2 more answers
What is the answer to these question?
Natali5045456 [20]

Answer:

2.  y = 7/2 x -2

3.   y = 3/4x-1

Step-by-step explanation:

points (0,-2)  (4,12)

slope = (y2-y1)/(x2-x1)

slope = (12--2)/(4-0)

    = (12+2)/4

   = 14/4 = 7/2

the slope is 7/2 and the y intercept is -2

y = mx+b

y = 7/2 x -2


points (0,-1)  (4,2)

slope = (y2-y1)/(x2-x1)

slope = (2--1)/(4-0)

    = (2+1)/4

   = 3/4

the slope is 3/4 and the y intercept is -1

y = mx+b

y = 3/4x-1

3 0
3 years ago
Which of the following equations is in slope intercept form
Nezavi [6.7K]
The answer is A bcs y=mx +c
7 0
4 years ago
Stephon makes the following statements: statement 1 lim x -3 f(x) exists and is equal to 1 statement 2 lim x 1 f(x) exists and i
Mandarinka [93]

Neither statement 1, nor statement 2 are correct

The given Stephon's statements are;

Statement 1; \mathbf{\lim \limits  _{x \to -3} f(x)}  \ \mathbf{Exist} \ and \mathbf{\lim \limits  _{x \to -3} f(x) = 1}

Statement 2; \mathbf{\lim \limits  _{x \to 1} f(x)}  \ \mathbf{Exist} \ and \mathbf{\lim \limits  _{x \to 1} f(x) = 1}

The analysis of the graph and reason for the answer

From the graphed line on the left of the y-axis, we have an open circle at x = -3, and an arrow at the other end pointing towards negative infinity, (-∞) which indicates that the domain is -∞ ≤ x < -3, therefore, at x = -3, f(x) does not exist, therefore, we can write the following statement

The limits of the domain and range of the graph includes;

\mathbf{\lim \limits  _{x \to -3} f(x)} = \mathbf{Does \ not \ exist}

f(x) = Defined for -∞ ≤ x < -3

Similarly, from the graphed line on the right of the y-axis, we have an open circle at x = 1 and an arrow at the other end of the line f(x) = 4 pointing towards positive (+∞) infinity, which indicates the domain and the graph of the function is 1 < x ≤ ∞ , therefore, f(x) does not exist at x = 1, and we can write

\mathbf{\lim \limits  _{x \to 1} f(x)} = \mathbf{Does \ not \ exist}

From we above, we have that neither statement 1, nor statement 2 are correct

Learn more about open and closed circles on graph lines

brainly.com/question/8648835

4 0
3 years ago
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