Answer:
x=34
Step-by-step explanation:
6 - ( x-7) ^ 1/3 = 3
Subtract 6 from each side
6-6 - ( x-7) ^ 1/3 = 3-6
- ( x-7) ^ 1/3 = -3
Divide each side by a negative
( x-7) ^ 1/3 = 3
Cube each side
( x-7) ^ 1/3 ^3 = (3)^3
x-7 = 27
Add 7 to each side
x-7+7 = 27+7
x = 34
Check
6 - ( 34-7) ^ 1/3 = 3
6 - (27^1/3 = 3
6 -3 =3
3=3
Good solution
Answer: a) 1 / ⁴⁰C₅ b) 0.33
Step-by-step explanation:
a) The sample space consists of all numbers 1-40.
Since any of the number can be taken from the sample space so each of five 5 distinct numbers we take has equal probability of occurring. So probability of each 5 numbers set we take will be equal to 1 / ⁴⁰C₅
b)
If we pick exactly 3 even number then that means other 2 will be odd.
So, we have sample space of 40 numbers out of which 20 are even and 20 are odd.
Now we have to pick 3 even out of 20 and 2 odd out of 20.
Probability = ²⁰C₃ * ²⁰C₂ / ⁴⁰C₅
Probability= 0.33
Answer:
5 2/3
Step-by-step explanation:
Just keep simplifying 8/12 until you end up with 2/3
Find the GCF of both the numerator and denominator and you end up with 2/3
Just to make it clear 8/12 = 2/3
Answer:
We accept the null hypothesis and conclude that voltage for these networks is 232 V.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 232 V
Sample mean, 
= 231.5 V
Sample size, n = 66
Sample standard deviation, s = 2.19 V
Alpha, α = 0.05
First, we design the null and the alternate hypothesis
We use Two-tailed t test to perform this hypothesis.
Formula:
Putting all the values, we have
Now,
Since,
We accept the null hypothesis and conclude that voltage for these networks is 232 V.
