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3 years ago

If 100 beach umbrellas have a mass of 865.2kg what is the mass of each umbrella

Mathematics

1 answer:

Readme [11.4K]3 years ago

8 0

Answer:

8.652kg

Step-by-step explanation:

100 beach umbrellas = 865.2kg

1 beach umbrella = 865.2/100 kg

1 beach umbrella = 8.652kg (Ans)

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Y=4 -2x у = -5 + 4х ||

kolezko [41]

Answer:

y=1

Step-by-step explanation:

y= 4 - 2x

y= -5 + 4x

4 - 2x = -5 + 4x

4 + 5 = 4x +2x

9 = 6x

9/6 = x

3/2 = x

y= 4 -2(3/2)

y = 4 - 3

y = 1

5 0

2 years ago

A small combination lock on a suitcase has 4 wheels, each labeled with the 10 digits 0 to 9. how many 4 digit combinations are

tamaranim1 [39]

This is the easiest way to solve this problem:

Imagine this represents how many combinations you can have for each of the 4 wheels (each blank spot for one wheel): __ __ __ __

For the first situation it says how many combos can we make if no digits are repeated.
We have 10 digits to use for the first wheel so put a 10 in the first slot
10 __ __ __
Since no digit can be repeated we only have 9 options for the second slot
10 9_ __ __
Same for the third slot, so only 8 options
10 9 8 __
4th can't be repeated so only 7 options left
10 9 8 7

Multiply the four numbers together: 10*9*8*7 = 5040 combinations

For the next two do the same process as the one above.

If digits can be repeated? You have ten options for every wheel so it would look like this: 10 10 10 10

10*10*10*10 = 10,000 combinations

If successive digits bust be different?
We have 10 for the first wheel, but second wheel only has 9 options because 2nd number can't be same as first. The third and fourth wheels also has 9 options for the same reason.

10 9 9 9 

10*9*9*9 = 7290 combinations

8 0

2 years ago

I NEED HELP ASAP ILL GIVE BRAINLIEST!

EleoNora [17]

Answer:

1/6

Step-by-step explanation:

4 0

1 year ago

Find the probability.

kvv77 [185]

Answer:

7/36

Step-by-step explanation:

1 die has 6 faces

When two dice are rolled, the total number of outcomes

= 6 × 6 = 36

The Probability of having(5) =

(1 & 4), (2 & 3) , ( 3 & 2), (4 & 1)

= 4

The probability of having (10) =

(5 & 5), (4 & 6) , ( 6 & 4)

= 3

The probability that the score on the dice is either 5 or 10.

P(5) + P(10)

= 4/36 + 3/36

= 7/36

8 0

2 years ago

In each of Problems 5 through 10, verify that each given function is a solution of the differential equation.

WARRIOR [948]

Answer:

For First Solution: $y_1(t)=e^t$

$y_1(t)=e^t$ is the solution of equation y''-y=0.

For 2nd Solution: $y_2(t)=cosht$

$y_2(t)=cosht$ is the solution of equation y''-y=0.

Step-by-step explanation:

For First Solution: $y_1(t)=e^t$

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

$y_1(t)=e^t$

First order derivative:

$y'_1(t)=e^t$

2nd order Derivative:

$y''_1(t)=e^t$

Put Them in equation y''-y=0

e^t-e^t=0

0=0

Hence $y_1(t)=e^t$ is the solution of equation y''-y=0.

For 2nd Solution:

$y_2(t)=cosht$

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

$y_2(t)=cosht$

First order derivative:

$y'_2(t)=sinht$

2nd order Derivative:

$y''_2(t)=cosht$

Put Them in equation y''-y=0

cosht-cosht=0

0=0

Hence $y_2(t)=cosht$ is the solution of equation y''-y=0.

3 0

3 years ago