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3 years ago

What's 506.25 roundest to the nearest whole

Mathematics

1 answer:

jonny [76]3 years ago

6 0

Answer:

506

Step-by-step explanation:

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Difference is 6 quotient is 2

Nataliya [291]

$the\ quotient\ =2\\\\therefore\ first\ number\ is\ 2\ times\ greater\ than\ the\ second\ number\\\\so,\ first\ number\ is\ 2x\ and\ second\ number\ is\ x.\\\\The\ difference\ =6\\\\therefore\\\\2x-x=6\Rightarrow x=6\ and\ 2x=2\times6=12\\\\Answer:\boxed{12\ and\ 6}$

3 0

3 years ago

Write the equation of a line that passes through the points (-4, -5) and (2, 13).

andrew11 [14]

(-4,-5)(2,13)
slope(m) = (y2 - y1) / (x2 - x1)
slope(m) = (13 - (-5) / (2 - (-4)
slope(m) = (13 + 5) / (2 + 4)
slope(m) = 18/6 = 3

y = mx + b
slope(m) = 3
(2,13)...x = 2 and y = 13
now we sub, we are looking for b, the y int
13 = 3(2) + b
13 = 6 + b
13 - 6 = b
7 = b

so ur equation is : y = 3x + 7

8 0

3 years ago

Find the area of the shaded figure.

Whitepunk [10]

I believe the answer is 12. I hope this helps you and have a great day!

4 0

3 years ago

HELPPP ASAP PLZZZ!!!!!

AleksandrR [38]

Answer:

its c

Step-by-step explanation:

why do I need to explain

6 0

3 years ago

A construction company employs two sales engineers. Engineer 1 does the work of estimating cost for 70% of jobs bid by the compa

netineya [11]

Answer:

Engineer 1

Step-by-step explanation:

Based on the information given:

P( 1 ) = 0.7

P( 2 ) = 0.3

P(A | B) is a conditional probability: the likelihood of event A occurring given that B is true.

P( E | 1 ) = 0.02

P( E | 2 ) = 0.04

Then P( E | 1 ) is the probability that an error occurs when engineer 1 does the work and P( E | 2 ) is the probability that an error occurs when engineer 2 does the work.

To have an idea of which engineer is more likely to do the work when an error occurs you need to calculate P( 1 | E ) and P( 2 | E ), The probability that engineer 1 does the work when an error occurs and the probability that engineer 2 does the work when an error occurs.

The Bayes's theorem states:

$P( B | A ) = \frac{P( A | B )*P( A )}{P( B )}$

Using the notation above:

$P( 1 | E ) = \frac{P( E | 1 )*P( 1 )}{P( E )}$

P( E ) = 0.7*0.02 + 0.3*0.04 = 0.026 /// the probability that engineer 1 does the work and an error occurs or the probability that engineer 2 does the work and an error ocurrs.

$P( 1 | E ) = \frac{0.04*0.3}{0.026}=0.538$

Doing the same for engineer 2:

$P( 2 | E ) = \frac{0.04*0.3}{0.026}=0.462$

6 0

3 years ago