Your question answers itself. You solve by graphing.
I like to subtract one side of the equation from the other, so the solutions are where the graph crosses the x-axis (the resulting function value is zero).
It can be useful to find the "turning point" of each absolute value expression (where its value is zero) and graph that and some points on either side.
Answer:
x≤−6
Step-by-step explanation:
Let's solve your inequality step-by-step.
4(x−3)−7x≥6
Step 1: Simplify both sides of the inequality.
−3x−12≥6
Step 2: Add 12 to both sides.
−3x−12+12≥6+12
−3x≥18
Step 3: Divide both sides by -3.
−3x
−3
≥
18
−3
x≤−6
If period of

is one-half the period of

and
<span>

has a period of 2π, then

and

.
</span>
To find the period of sine function

we use the rule

.
<span /><span />
f is sine function where f (0)=0, then c=0; with period

, then

, because

.
To find a we consider the condition

, from where

.
If the amplitude of

is twice the amplitude of

, then

has a product factor twice smaller than

and while period of

<span> </span> is 2π and g(0)=0, we can write

.
Answer:
Last one
Step-by-step explanation: