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2 years ago

6

Which congruence criteria can be used directly from the information about triangles HIJ and MNO to prove IJ¯¯¯¯¯¯≅MN¯¯¯¯¯¯¯¯¯¯ b

y CPCTC? HI¯¯¯¯¯¯¯≅NO¯¯¯¯¯¯¯¯, ∠I≅∠N, ∠H≅∠O

1 answer:

amid [387]2 years ago

7 0

Answer:

AAS

Step-by-step explanation:

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What ia the common ratio of the sequence? -2 , 6, -18, 54,...

Jlenok [28]

Its a multiplication by -3 on each term, so I think you're gonna answer is by r=-3, maybe?

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3 years ago

Solve for x show all work -2× + 5=4× -7

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On a coordinate plane, triangles R S T and L M N are shown. Triangle R S T has points (5, 5), (2, 1), and (1, 3). Triangle L M N

ivolga24 [154]

Answer:

LMN has a larger area

Step-by-step explanation:

Given

RST

$R =(5,5)$

$S= (2,1)$

$T = (1,3)$

LMN

$L = (0,-1)$

$M= (2,-4)$

$N= (-2,-3)$

Required

Compare both areas

The area of triangle is:

$Area = \frac{1}{2}|x_1y_2 - x_2y_1 + x_2y_3 - x_3y_2 + x_3y_1 - x_1y_3|$

For RST, we have:

$Area = \frac{1}{2}|5*1 - 2*5 + 2*3 - 1*1 + 1*5 - 5*3|$

$Area = \frac{1}{2}|-10|$

Remove absolute signs

$Area = \frac{1}{2}*10$

$Area = 10$

For LMN, we have:

$Area = \frac{1}{2}|x_1y_2 - x_2y_1 + x_2y_3 - x_3y_2 + x_3y_1 - x_1y_3|$

$Area = \frac{1}{2}|0*-4-2*-1+2*-3--2*-4--2*-1-0*-3|$

$Area = \frac{1}{2}|-14|$

Remove absolute signs

$Area = \frac{1}{2}*14$

$Area = 7$

<em>By comparing both areas, we can conclude that LMN has a larger area</em>

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72/8 = 9 ml

There would be 9 ml of water in each of the first 8 beakers.

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3 years ago

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Answer:

He would need 58 yards of material.

Step-by-step explanation:

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2 years ago

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