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Diano4ka-milaya [45]
3 years ago
7

How can I trust your guys

Mathematics
2 answers:
Zinaida [17]3 years ago
7 0

Answer:

Step-by-step explanation:

you just do, everyone in here needs help so i dont think theres people in here just messing arround, you can trust.

STatiana [176]3 years ago
6 0

Answer:

because we are amazing as always.

Step-by-step explanation:

Please dont do this or i will report u.

bye

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You are a supervisor for a home cleaning business,
irinina [24]

Answer:

option a

Step-by-step explanation:

i think this because my teacher in my business class stated this before to the whole class but I was distracted so it can totally be wrong if it is my bad

8 0
2 years ago
What is the first step in writing f(x) = 6x2 + 5 – 42x in vertex form?
Marat540 [252]
F(x) = 6x² + 5 - 42x

first step in writing the f(x) in vertex form? WRITE THE FUNCTION IN STANDARD FORM.

f(x) = 6x² - 42x + 5

Exponents must be in decreasing order. 
7 0
3 years ago
Read 2 more answers
Will give BRAINLEST :)
DiKsa [7]

Answer:

A

Step-by-step explanation:

This explanation mostly depends on what you're learning right now. The first way would be to convert this matrix to a system of equations like this.

g + t + k = 90

g + 2t - k = 55

-g - t + 3k = 30

Then you solve using normal methods of substitution or elimination. It seems to me that elimination is the quickest method.

g + t + k = 90

-g - t + 3k = 30

____________

0 + 0 + 4k = 120

4k = 120

k = 30

No you can plug this into the first two equations

g + t + (30) = 90

g + t = 60

and

g + 2t - (30) = 55

g + 2t = 85

now use elimination again by multiplying the first equation by -1

g + 2t = 85

-g - t = -60

_________

0 + t = 25

t = 25

Now plug those both back into one of the equations. I'll just do the first one.

g + (25) + (30) = 90

g = 35

Therefore, we know that Ted spent the least amount of time on the computer.

The second method is using matrix reduction and getting the matrix in the row echelon form, therefore solving using the gauss jordan method. If you would like me to go through this instead, please leave a comment.

3 0
3 years ago
How do you solve it?
MatroZZZ [7]

Answer:

<em>i: </em>x=-2, x=1

<em>ii: </em>x=-1/2

Step-by-step explanation:

Quadratic form:

You solve <em>i </em>by using FOIL (First, Outside, Inside, Last) because it is a multiplication problem.

(x+2)(x-1)=0

<em>"first"</em> would be x*x, which would equal x^{2}

<em>"outside"</em> would be x*-1, which would equal -1x, or -x

<em>"inside"</em> would be 2*x, which would equal 2x

<em>"last" </em>would be 2*-1, which would equal -2

Now you need to combine the terms so that they are one after the other

x^{2}-x +2x-2

Combine like terms, and you should get:

x^{2} +x-2

i Solution

<em>You need to get the variable by itself.</em>

<em>Subtract two from both sides</em>

x+2=0\\x=-2

<em>Add one to both sides.</em>

x-1=0\\x=1

ii Solution

<em>Add all the terms.</em>

x+2+x-1=0\\2x+1=0\\2x=-1\\x=-\frac{1}{2}

8 0
3 years ago
write a polynomial function of least degree with integral coefficients that has the given zeros. -(1/3), -i
inessss [21]

Answer:

f(x)=3x^3+x^2+3x+1

Step-by-step explanation:

If a real number -\frac{1}{3} is a zero of polynomial function, then

x-\left(-\dfrac{1}{3}\right)=x+\dfrac{1}{3}

is the factor of this function.

If a complex number -i is a xero of the polynomial function, then the complex number i is also a zero of this function and

x-(-i)=x+i\ \text{ and }\ x-i

are two factors of this function.

So, the function of least degree is

f(x)=\left(x+\dfrac{1}{3}\right)(x+i)(x-i)=\left(x+\dfrac{1}{3}\right)(x^2-i^2)=\\ \\ =\left(x+\dfrac{1}{3}\right)(x^2+1)=\dfrac{1}{3}(3x+1)(x^2+1)=\dfrac{1}{3}(3x^3+x^2+3x+1)

If the polynomial function must be with integer coefficients, then it has a form

f(x)=3x^3+x^2+3x+1

4 0
4 years ago
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