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Margaret [11]
3 years ago
10

What is the 6th term of the geometric sequence shown?

Mathematics
1 answer:
solniwko [45]3 years ago
8 0

Answer:

0

Step-by-step explanation:

subtract 20 from 40 it's Zero

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FIRST GETS BRAINIEST Write a story problem in which you would have to multiply 5 × (-1/3)
AveGali [126]

Answer:

5 students from Westville Elementary school re on a field trip. They come to a hot dog stand and no one has money. One student's parents has a tab at the hot dog stand. So the student, along with the four others, decide to order food and put it on the tab. Each hot dog is 1/3 of a dollar. They would like to know how much they are in debt.

5 times the negative (-1/3) for each hot dog.

-1 and 2/3 dollars

Glad I was able to help!!

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3 years ago
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Find three consecutive odd integers such that the sum of the 1st and 2nd number is 344
olga2289 [7]

Answer:

three consecutive odd integers are.

171, 173, 175

Step-by-step explanation:

Let x be the first term of odd integer,

Therefore, the second consecutive odd integers = x+2

Similarly, the third consecutive odd integers = x+4

Given:

The sum of the first term and second term is 344.

first term + second term = 344

Here first term is x and second term is x+2.

x+(x+2)=344

2x+2=344

2x=344-2

x=\frac{342}{2}

x=171

Therefore, the first odd integers is 171.

And the second consecutive odd integers = x+2=171+2=173

Similarly, the third consecutive odd integers = x+4=171+4=175

8 0
3 years ago
What is the answer to 6 2/7 * 2 1/ 10
mixas84 [53]

Answer:

13.2

Step-by-step explanation:

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Questions 16-17 | Math 1 - 0 points Solve the graph Help needed !!
iris [78.8K]

Answer:

16) The area of the circle is 25.1 units²

17) JKLM is a parallelogram but not a rectangle

Step-by-step explanation:

16) Lets talk about the area of the circle

- To find the area of the circle you must find the length of the radius

- In the problem you have the center of the circle and a point on

 the circle, so you can find the length of the radius by using the

 distance rule

* Lets solve the problem

∵ The center of the circle is (1 , 3)

∵ The point on the circle is (3 , 5)

- Using the rule of the distance between two points

* Lets revise it

- The distance between the two points (x1 , y1) and (x2 , y2) is:

 Distance = √[(x2 - x1)² + (y2 - y1)²]

∴ r = √[(3 - 1)² + (5 - 3)²] = √[4 + 4] = √8 = 2√2 units

∵ The area of the circle = πr²

∴ The area of the circle = π (2√2)² = 8π = 25.1 units²

* The area of the circle is 25.1 units²

17) To prove a quadrilateral is a parallelogram, prove that every

     to sides are parallel or equal or the two diagonal bisect

     each other

* The parallelogram can be rectangle if two adjacent sides are

  perpendicular to each other (measure of angle between them is 90°)

 or its diagonals are equal in length

- The parallel lines have equal slopes, then to prove the

  quadrilateral is a parallelogram, we will find the slopes of

  each opposite sides

* Lets find from the graph the vertices of the quadrilateral

∵ J = (0 ,2) , K (2 , 5) , L (5 , 0) , M (3 , -3)

- The opposite sides are JK , ML and JM , KL

- The slope of any line passing through point (x1 , y1) and (x2 , y2) is

 m = (y2 - y1)/(x2 - x1)

∵ The slop of JK = (5 - 2)/(2 - 0) = 3/2 ⇒ (1)

∵ The slope of LM = (-3 - 0)/(3 - 5)= -3/-2 = 3/2 ⇒ (2)

- From (1) and (2)

∴ JK // LM

∵ The slope of KL = (0 - 5)/(5 - 2) = -5/3 ⇒ (3)

∵ The slope of JM = (-3 - 2)/(3 - 0)= -5/3 ⇒ (4)

- From (3) and (4)

∴ KL // JM

∵ Each two opposite sides are parallel in the quadrilateral JKLM

∴ It is a parallelogram

- The product of the slopes of the perpendicular line is -1

* lets check the slopes of two adjacent sides in the JKLM

∵ The slope of JK = 3/2 and the slope of KL = -5/3

∵ 3/2 × -5/3 = -5/2 ≠ -1

∴ JKLM is a parallelogram but not a rectangle

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3 years ago
What number is 35% of 22
Ierofanga [76]
Go 0.35•22 and you get 7.7
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