Given :
Kiara spent $28 on 4 ribbons and 5 balloons.
Sarah spent $28 on 8 ribbons and 3 balloons.
To Find :
The cost of each ribbon and each balloon.
Solution :
Let, cost of each ribbon is x and balloon is y.
For situation 1 :
4x + 5y = 28 ...1)
For situation 2 :
8x + 3y = 28 ...2)
Multiplying equation 1) by 2 and subtracting equation 2) by it :
2( 4x + 5y ) - ( 8x + 3y ) = 2 × 28 - 28
10y - 3y = 28
y = 4
Putting value of y in equation 1) , we get :
Therefore, the cost of each ribbon and each balloon is $2 and $4 respectively.
Answer:
D. Range
Step-by-step explanation:
The definition of range is as the question says, and we can also use the process of elimination to make sure it's not the others.
A mean is the average of a data set.
A mode is the item that appears the most times.
And a median is the middle number.
As you can see, A, B, C all don't fit the given statement in the question, so it is D. Range.
I hope this helped! :D
Answer:
-3/2
Step-by-step explanation:
6=|x|+3-x
move the terms
-|x|+x=3-6
-|x|+x=-3
-x+x=-3 , x > 0 (put a line under >)
-(-x)+x=-3 , x < 0
-3/2 , x < 0 find the intersection
x= -3/2
if you dont want it as a fraction you can do -1.5 in decimal form
60(1+.04)x^2 goes through the origin
