Answer:

Step-by-step explanation:

Applying the Laplace transform:
![\mathcal{L}[y'']+5\mathcal{L}[y']+4\mathcal{L}[y']=0](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5By%27%27%5D%2B5%5Cmathcal%7BL%7D%5By%27%5D%2B4%5Cmathcal%7BL%7D%5By%27%5D%3D0)
With the formulas:
![\mathcal{L}[y'']=s^2\mathcal{L}[y]-y(0)s-y'(0)](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5By%27%27%5D%3Ds%5E2%5Cmathcal%7BL%7D%5By%5D-y%280%29s-y%27%280%29)
![\mathcal{L}[y']=s\mathcal{L}[y]-y(0)](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5By%27%5D%3Ds%5Cmathcal%7BL%7D%5By%5D-y%280%29)
![\mathcal{L}[x]=L](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5Bx%5D%3DL)

Solving for 




Apply the inverse Laplace transform with this formula:
![\mathcal{L}^{-1}[\frac1{s-a}]=e^{at}](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5E%7B-1%7D%5B%5Cfrac1%7Bs-a%7D%5D%3De%5E%7Bat%7D)
![y=3\mathcal{L}^{-1}[\frac1{s+4}]=3e^{-4t}](https://tex.z-dn.net/?f=y%3D3%5Cmathcal%7BL%7D%5E%7B-1%7D%5B%5Cfrac1%7Bs%2B4%7D%5D%3D3e%5E%7B-4t%7D)
Answer:
<h2>
∠PQT = 72°</h2>
Step-by-step explanation:
According to the diagram shown, ∠OPQ = ∠OQP = 18°. If PQT is a tangent to the circle, it can be inferred that line OQ is perpendicular to line QT. Ths shows that ∠OQT = 90°.
Also from the diagram, ∠OQP + ∠PQT = ∠OQT;
∠PQT = ∠OQT - ∠OQP
Given ∠OQP = 18° and ∠OQT = 90°
∠PQT = 90°-18°
∠PQT = 72°
Answer:
L = 20
W = 10
Step-by-step explanation:
L = (w + 10)
NL = (w + 13)
Divide 299 by 13:
299 ÷ 13 = 23
So, 23 x 13 = 299
L = 23
W = 13
Subtract 3 from both to get the original length and width
Answer:
<u>The correct answer is C. It is the original amount of money the bank loans the borrower.</u>
Step-by-step explanation:
Let's recall that are five basic elements for calculating the payment of a loan:
1. The principal. How much money you borrow.
2. The interest rate. How much money you will pay in addition to the principal.
3. The period of time. How long will it takes you to pay the loan.
4. The frequency of payment. Will you pay every month?, every quarter?, every year or maybe every two weeks?
5. Additional payments. When you have additional income seasonally and you want to lower either the period of time or the interests to pay.
Answer:
42.5 units^2
Step-by-step explanation:
We can split up this shape into smaller ones.
First we can start with the large rectangle on top
We know its 9 by 3.5
9x3.5=31.5
The large rectangle is 31.5, at the end we'll add them all together
Next we can work on the small triangle on the bottom left
Area= bh/2
Both the base and height are 2, 2x2=4 4/2=2, The area of that triangle is 2
Now we can work on the triangle on the bottom right. This time the base is 5
5x2=10 10/2=5, The area of that triangle is 5
Now we need to figure out the square/rectangle at the bottom. We only know one side is 2. We can figure out the top side. Since the very top of the shape is 9, we know that the bottom side of the large rectangle also has to add to 9. We know the values 2 and 5. 2+5+x=9, the missing length that's there is 2.
Now we know the small square is 2 by 2. 2x2=4 The square's area is 4
Now we add them all up.
31.5+2+5+4=42.5