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mafiozo [28]
2 years ago
5

The sum of two numbers is 88 and the second number is 30 more than the first number what is the number and we’re doing writing

systems
Mathematics
2 answers:
Finger [1]2 years ago
8 0
2X+30=80
2X=50
X=25
First num=25
Second num=55
Gnoma [55]2 years ago
8 0

Answer:

29 & 59

Step-by-step explanation:

x+x+30 = 88

2x + 30 = 88

2x = 58

x = 29

the two numbers are 29 and 59

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4,567.89
In-s [12.5K]

Answer:

I got 40210.1

Step-by-step explanation:

4,567.89+7,894.56=12462.45

12462.45+1,232.45=13694.9

13694.9+1,474.10=15169

15169+2,585.20=17754.2

17754.2+3696.36=21450.56

21450.56+3,214.56=24665.12

24665.12+6,545.65=31210.77

31210.77+7,898.78=39109.55

39109.55+1.100.55=40210.1

5 0
2 years ago
HELP !!!!!!MEEEEEEEEEEEE!!!!!!!!!!
LUCKY_DIMON [66]

Answer: Ray B

Step-by-step explanation:

5 0
2 years ago
What is the inverse equation for h(x) = 2log(x-3) ?
marshall27 [118]

Given the function:

h(x)=2log\left(x-3\right)

To find its inverse:

\begin{gathered} y=2log\left(x-3\right) \\ x=2log\left(y-3\right) \end{gathered}

solving for y:

\frac{x}{2}=log(y-3)\begin{gathered} 10^{\frac{x}{2}}=y-3 \\  \\ 10^{\frac{x}{2}}+3=y \end{gathered}

ANSWER

h^^{-1}(x)=10^{\frac{x}{2}}+3

8 0
1 year ago
The nth term of a sequence is 3n²-1
Anarel [89]

Answer: The number is 26.

Step-by-step explanation:

We know that:

The nth term of a sequence is 3n²-1

The nth term of a different sequence is 30–n²

We want to find a number that belongs to both sequences (it is not necessarily for the same value of n) then we can use n in one term (first one), and m in the other (second one), such that n and m must be integer numbers.

we get:

3n²- 1 =  30–m²

Notice that as n increases, the terms of the first sequence also increase.

And as n increases, the terms of the second sequence decrease.

One way to solve this, is to give different values to m (m = 1, m = 2, etc) and see if we can find an integer value for n.

if m = 1, then:

3n²- 1 =  30–1²

3n²- 1 = 29

3n² = 30

n² = 30/3 = 10

n² = 10

There is no integer n such that n² = 10

now let's try with m = 2, then:

3n²- 1 =  30–2² = 30 - 4

3n²- 1 = 26

3n² = 26 + 1 = 27

n² = 27/3 = 9

n² = 9

n = √9 = 3

So here we have m = 2, and n = 3, both integers as we wanted, so we just found the term that belongs to both sequences.

the number is:

3*(3)² - 1 = 26

30 - 2² = 26

The number that belongs to both sequences is 26.

6 0
2 years ago
The product of 263 and v is equal to the quotient of 215 and r
sveticcg [70]

Answer:

263 · v = 215 ÷ r

Step-by-step explanation:

I hope this helps!

3 0
2 years ago
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