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vlabodo [156]
3 years ago
8

Please help asap!!! What are the image points

Mathematics
1 answer:
DerKrebs [107]3 years ago
3 0
Bbshehshsjehebnnejenwnsbwnsnsnsne

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How many solutions does 4(x-1)-x = 3(x+5)-11 have
bonufazy [111]

Answer:

None.

Step-by-step explanation:

4(x-1)-x = 3(x+5)-11

4x-4-x=3x+15-11

we combine like terms.

4x-x-4=3x+14

3x-4=3x+14

we then isolate the variables.

3x-4=3x+14

   +4       +4

3x=3x+18

-3x -3x

0≠18

No solutions

6 0
3 years ago
If an 8 hour work day includes a total break time of 22 1/4%, how many hours are used for breaks?
torisob [31]

Answer:

1 39/50 hours. This is equivalent to 1.78 hours.

Step-by-step explanation:

The sum of the hours of work and the hours for break gives the work day hour which has been given as 8 hours.

Furthermore, given that the break time is 22 1/4%, the number of hours for break

= 22 1/4% × 8 hours

= 89/400 × 8

= 1 39/50 hours

4 0
3 years ago
Solve for x: x/5 = 75
Ainat [17]

Answer:

x=15

Step-by-step explanation:

75/5=x  15x5=75

6 0
3 years ago
Read 2 more answers
Place values and whole number
LenKa [72]
9. ( 1×10,000)+(5×1,000)+(4×100)+(9×1) ; fifteen thousand , four hundred - nine
7 0
4 years ago
If sin(x) = 5/13, and x is in quadrant 1, then tan(x/2) equals what?
Rufina [12.5K]
x is in quadrant I, so 0, which means 0, so \dfrac x2 belongs to the same quadrant.

Now,

\tan^2\dfrac x2=\dfrac{\sin^2\frac x2}{\cos^2\frac x2}=\dfrac{\frac{1-\cos x}2}{\frac{1+\cos x}2}=\dfrac{1-\cos x}{1+\cos x}

Since \sin x=\dfrac5{13}, it follows that

\cos^2x=1-\sin^2x\implies \cos x=\pm\sqrt{1-\left(\dfrac5{13}\right)^2}=\pm\dfrac{12}{13}

Since x belongs to the first quadrant, you take the positive root (\cos x>0 for x in quadrant I). Then

\tan\dfrac x2=\pm\sqrt{\dfrac{1-\frac{12}{13}}{1+\frac{12}{13}}}

\tan x is also positive for x in quadrant I, so you take the positive root again. You're left with

\tan\dfrac x2=\dfrac15
4 0
3 years ago
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