Answer:
im sorry i cant help you without a picture
Step-by-step explanation:

There are 2 roots so the only way to complete the square is,
![y=2x^2+8x-9\\y=2[(x^2+4x)]-9\\y=2[(x^2+4x+4)-4]-9\\y=2[(x+2)^2-4]-9\\y=2(x+2)^2-8-9\\y=2(x+2)^2-17](https://tex.z-dn.net/?f=y%3D2x%5E2%2B8x-9%5C%5Cy%3D2%5B%28x%5E2%2B4x%29%5D-9%5C%5Cy%3D2%5B%28x%5E2%2B4x%2B4%29-4%5D-9%5C%5Cy%3D2%5B%28x%2B2%29%5E2-4%5D-9%5C%5Cy%3D2%28x%2B2%29%5E2-8-9%5C%5Cy%3D2%28x%2B2%29%5E2-17)
Just factor 2 out of 2x^2+8x (just ignore the -9) then find the number that will make the terms be able to complete the square.
then complete the square and multiply 2 inside the brackets.
subtraction as you already get the vertex form and know how to complete the square.
Vertex Form: 
8,192 because
1 on 1
2 on 2
4 on 3
8 on 4
16 on 5
32 on 6
64 on 7
128 on 8
256 on 9
512 on 10
1024 on 11
2048 on 12
4096 on 13
8192 on 14
6 dimes, 12 nickles, 2 quarters and 2 nickles and 2 quarters and a dime.
There are many ways to do this.
Answer:
3x-2y
Step-by-step explanation:
2y must be subracted