Answer:
The vertex form parabola y = 2( x+4)² -37
Step-by-step explanation:
<u>Step(i):-</u>
Given parabola equation j(x) = 2x² + 8x -5
Let y = 2x² + 8x -5
⇒ y = 2(x² + 2(4x)+(4)²-(4)²) -5
By using (a + b)² = a² +2ab +b²
y = 2(x+4)²- 32 -5
y = 2 ( x-(-4))² -37
<u><em>Step(ii):-</em></u>
The vertex form parabola y = a( x-h)² +k
The vertex form parabola y = 2(x+4)² -37
Any picture? Example: if the number is 36 you would round to 40 and if the number was 34 you would round to 30 if it is 35 you choose what to round to. It depends on the last digit.
Step-by-step explanation:
f(x) × g(x)
= (x2 + 5x )× (3x2 -4x )
=3x4 + 15x3 - 4x3 -20x2
3x^4 + 11 x3 - 20x2
H = -5t^2 +5t + 10
a) t = 0, h = 10 at time 0
b) h = (-5t + 10) ( t + 1)
c) put 0 in for the height and set each factor = to 0 and solve each
0 = (-5t + 10) and 0 = (t + 1)
solve each t = 2 and t = -1, so t = 2 sec is your solution
d) because a parabola is symmetric, the max will be half way between -1 and 2, at t = 1/2
h = -5(1/2)^2 +5(1/2) + 10
h = -5(1/4) + 5/2 +10
h = -5/4 + 5/2 + 10
h = -5/4 + 10/4 + 40/4
h = 45/4
Solve the equation:
– 3b – (– 2) = 4b <span>– 12
</span>– 3b + 2 = 4b – 12
– 3b = 4b – 12 – 2
– 3b = 4b – 14
– 3b – 4b = – 14
– 7b = – 14
– 14
b = ———
– 7
b = 2 <——— solution.
I hope this helps. =)
