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2 years ago

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A right triangle is formed by connecting coordinates (5, -2), (2, -3), and (-1, 6). What is the area of the triangle in square u

nits?

1 answer:

Marianna [84]2 years ago

8 0

Answer:

the triangle formed from the coords is 3cm by 9cm so try 3 × 9 = 27 then 27 ÷ 2 = 13.5 from the formula a = ½bh?

Step-by-step explanation:

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A rope of length 18 feet is arranged in the shape of a sector of a circle with central angle O radians, as shown in the

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Answer:

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Step-by-step explanation:

The picture of the question in the attached figure

step 1

Let

r ---> the radius of the sector

s ---> the arc length of sector

Find the radius r

we know that

$2r+s=18$

$s=r \theta$

$2r+r \theta=18$

solve for r

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step 2

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substitute the value of r

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step 3

we know that

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$A=\pi r^{2}$

The complete circle subtends a central angle of 2π radians

so

using proportion find the area of the sector by a central angle of angle theta

Let

A ---> the area of sector with central angle theta

$\frac{\pi r^{2} }{2\pi}=\frac{A}{\theta} \\\\A=\frac{r^2\theta}{2}$

substitute the value of r

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$A=\frac{162 \theta}{(\theta+2)^2}$

Convert to function notation

$A(\theta)=\frac{162 \theta}{(\theta+2)^2}$

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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