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2 years ago

Write the equation for what is 15% of 24 of what number. please include the equation too

Mathematics

1 answer:

matrenka [14]2 years ago

4 0

Sorry i don’t know the answer maybe some one else knows

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HELP HELP HELP I DONT HAVE TIME HELPPP

Thepotemich [5.8K]

Answer:

Step-by-step explanation:

its false

4 0

2 years ago

Please help me again one last time for this lol.

Darina [25.2K]

Answer:

3/8 = 9/24 ; 1/3 = 8/24 ; 3/8 > 1/3

Step-by-step explanation:

You have to multiply 8 and 3 to obtein the same number as denominatoe (24).

Once you have the same number you can use < = >

3 0

3 years ago

(6^-8)^4

KIM [24]

Your Answer is A.

(-8) x 4

= -8 x 4

= -32

= 1/6 ^32

HOPE THIS HELPS!!

PLEASE MARK ME AS BRAINLIEST!!

5 0

3 years ago

Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.

Aleks [24]

Answer:

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

Step-by-step explanation:

The actual Series is::

$\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$

The method we are going to use is comparison method:

According to comparison method, we have:

$\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n$

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

$=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}$

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}$

Now:

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}$

So a_n is finite, so it converges.

Similarly b_n converges according to p-test.

P-test:

General form:

$\sum_{n=1}^{inf}\frac{1}{n^p}$

if p>1 then series converges. In oue case we have:

$\sum_{n=1}^{inf}b_n=\frac{1}{n^4}$

p=4 >1, so b_n also converges.

According to comparison test if both series converges, the final series also converges.

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

5 0

3 years ago

A basketball team played 15 games and won 80% of them. If the team expects to play 30 games in all, how many more games must it

emmainna [20.7K]

So 80% of 15 games won equal 12 games won and 3 lost. This is because 15/10 = 1.5 and 1.5 x 8 =12.
For 30, you do the exact same thing but with 90% instead. 30/10 = 3. 3 x 9 = 27.
So they need to have won 27 games to get a 90% winning percentage out of 30 games.
But since the question asks how many MORE games they need to play, it'll be 27-12 = 15.
So they need to win 15 more games to get a 90% winning percentage

5 0

3 years ago

Write the equation for what is 15% of 24 of what number. please include the equation too ​

Write the equation for what is 15% of 24 of what number. please include the equation too