He put 12 stamps in his collection.
Answer :
<u>Given</u><u> </u><u>-</u>
- Books read by aya = 5
- Total number of books read by them = 14
<u>To</u><u> </u><u>find</u><u> </u><u>-</u>
- How many books does luka reads.
<u>Solution</u><u> </u><u>-</u>
Here, total number of books is 14 and books read ny aya is 5 . To find the luka reads We'll subtract total number of books read by them from books read by aya.
→ 14 - 5
→ 9
<u>There</u><u>fore</u><u>,</u><u> </u><u>9</u><u> </u><u>books</u><u> </u><u>read</u><u> </u><u>by</u><u> </u><u>luka</u><u>.</u><u> </u>
Answer:
(-00, 00)
Step-by-step explanation:
(-infinity, infinity)

- The name of the circle is <u>IJKL</u>
- The name of central Angle

- The name of the secant = <u>KL</u>
Circle :- It is a round figures, which has no end points.
Central angle :- It the angle ,which lie in the middle of the circle.
- Here, H is the mid point of the circle .So, Angle IHJ is the central angle.
Secant :- A line drawn in circle in such a way that it intersect the circle from two distinct points. Then, It is called secant .
- Here, KL is the line which acts as a secant because it intersect the circle from point K and point L.

- Semicircle = FGH and FIH
- Minor Arc :- FG or GH
- Major Arc :- FHG or GFH
Semicircle :- Semicircle is nothing but the half of the circle.
<u>Here</u><u>, </u><u>In </u><u>second </u><u>diagram </u>
- FGH and FIH are acting as two semicircles which simulatineously forming one circle.
Minor Arc :- Minor Arc is nothing but the smaller arc of the circle and it is always smaller than the half of the circle that is semicircle.
<u>Here</u><u>, </u>
- FG or GH are the minor arc of the given circle.
Major Arc :- Major Arc is nothing but the largest arc of the circle and it is always larger than the half of the circle that is semicircle.
<u>Here</u><u>, </u>
- FHG or GFH is the major arc as it is larger than the semicircle of the given circle .
13. 10-14
14.I can't see the whole graph, so you need to do it yourself. Add up everyone's age and divide by the amount of people on the graph. That will give you the average.