Answer:
5/9
Step-by-step explanation:
Let the probability of getting a multiple of 3 is "A"
Let the probability of getting an even number is "B"
Total number of outcomes=36
Total number of favourable outcomes of either a multiple of 3 or an even number are
(1,1) ,(1,2) ,(2,1) ,(1,3) ,(3,1) ,(2,2) ,(1,5) (5,1) ,(3,3) ,(2,4) ,(4,2) ,(2,6) ,(6,2) ,(3,5) ,(5,3) ,(4,4) ,(6,4) ,(4,6) ,(5,5) ,(6,6)
That is we have 20 favourable outcomes
Hence, Probability=\frac{\text{favourable outcomes}}{\text{total number of outcomes}}Probability=
total number of outcomes
favourable outcomes
Therefore, after substituting the values we get
probability=\frac{20}{36}probability=
36
20
After simplification we will get
probability=\frac{5}{9}probability=
9
5
