Question

Pls help will mark brainliest

Answer 1

Answer:

$\large \boxed{ \boxed{ \tt x \geqslant 2 \: \: is \: \: the \: \: domain \: \: of \: \: function}}$

Step-by-step explanation:

We are given the square root function below:

$\large{g(x) = \sqrt{x - 2} }$

Recall that domain is the set of all x-values and that a number inside the square root cannot be negative.

From the given square root function above, substituting x >= 2 gives a positive output. But if we substitute x < 2, evaluating the numbers inside result in negative number in the square root which does not exist in Real Number.

Hence,

$\large{y = \sqrt{x - a} }$

And thus, the domain is

$\large \boxed{x \geqslant a}$

Since if x < a, the output would become an imaginary number.

From the given function,

$\large{g(x) = \sqrt{x - 2} }$

From the form of sqrt(x-a) where domain is a-term which is 2.

Since a = 2, and thus

$\large \boxed{x \geqslant 2}$