We know that
The exterior angle measures of a polygon must add up to 360°,
therefore
360°/72°=5 exterior angles
so
5 exterior angles, would mean 5 interior angles and therefore 5 sides to the polygon
The exterior angle and the interior angle of any polygon are supplementary and must add up to 180°.
exterior angle+interior angle=180°
interior angle=180°-exterior angle
interior angle=180°−72°-------> 108°
Each interior angle is 108°
The sum of the interior angles would be
5*108°=540°
the answer is
540°
I’m pretty sure k=59 degrees since the area of a triangle is 180 so you just subtract the angles you already have to find the other one
Answer:
Step-by-step explanation:
- log8(216) + [log(42) - log(6)] ÷ log(49) =
- log (216)/ log (8) + [log (7) + log (6) - log (6)] ÷ 2 log (7) =
- 3 log (3) log (2) / 3 log (2) + log (7) / 2 log (7) =
- 3 log (3) + 1/2
So standard form is Ax+By=C
Since the problem is already in that form you don’t need to switch it around however A has to be more than 0 (so positive). Divide the equation by -3 to get the answer x-4y=-8
