If 1 inch is 500 miles, then 4 inches is how many miles?
2 answers:
Answer:
2,000 miles
Step-by-step explanation:
We are given:
This can be rewritten as:
This is representative of a unit rate, as we have a in the denominator. To calculate the number of miles in
inches, simply multiply the unit rate by
:
This can rewritten as:
Therefore, there are 2,000 miles in 4 inches.
-
We can check our solution by simplifying the fraction by dividing both
and
by
to see if we achieve the unit rate:
Since this is in fact the unit rate, our solution is correct!
You might be interested in
Answer:
The origination fee on a mortgage of $400,000 is $7,000.
Step-by-step explanation:
Here, the mortgage value = $400,000
The origination fee = 1.75%
Now, the origination fee is calculated on the amount mortgaged.
⇒ 1.75 % of ($400,00) = Origination Fee
Now, 1.75 % of ($400,00) =
or, 1.75 % of ($400,00) = $ 7,000
Hence, the origination fee on a mortgage of $400,000 is $7,000.
Answer:
68.76% probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 50 employees will be at most $50
Step-by-step explanation:
To solve this question, we have to understand the normal probability distribution and the central limit theorem.
Normal probability distribution:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central limit theorem:
The Central Limit Theorem estabilishes that, for a random variable X, with mean and standard deviation
, a large sample size can be approximated to a normal distribution with mean
and standard deviation, which is also called standard error
In this problem, we have that:
What is the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 50 employees will be at most $50
This is the pvalue of Z when X = 1000+50 = 1050 subtracted by the pvalue of Z when X = 1000-50 = 950. So
X = 1050
By the Central Limit Theorem
has a pvalue of 0.8438
X = 950
has a pvalue of 0.1562
0.8438 - 0.1562 = 0.6876
68.76% probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 50 employees will be at most $50