Answer:
$8950.37
Step-by-step explanation:
Use the compound amount formula A = P(1 + r/n)^(nt), in which P is the initial amount of money (the principal), r is the interest rate as a decimal fraction, n is the number of times per year that interest is compounded, and t is the number of years.
Here we have A = $11,000, n = 2, r = 0.07 and t = 3, and so:
$11,000 = P(1 + 0.07/2)^(2*3), or
$11,000 = P (1.035)^6
$11,000 $11,000
Solving for P, we get P = ---------------- = ------------- = $8950.37
1.035^6 1.229
Depositing $8950.37 with terms as follows will result in an accumulation of $11,000 after 3 years.
After nine years the salaries will be the same
28000 3600031000 3800034000 4000037000 4200040000 4400043000 4600046000 4800049000 5000052000 52000
-|2x+3| > 2 and <span>-|2x+3| > - 2
</span>-2x+3 > 2
-2x > 2 - 3
-2x > -1
-2x / -2 > -1 / -2
x < 1/ 2
-|2x+3| > - 2
x < 5/2
Answer:
148/100=37/25
Step-by-step explanation:
Who have to think how many zeros it took for the decimal to get between the 1 and 4.
148/100=37/25 is your answer.