There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
Answer:
(8, 0)
(-2, 0)
(-3, 0)
Step-by-step explanation:
x - 8 = 0
x = 8
x + 2 = 0
x = -2
x + 3 = 0
x = -3
Step-by-step explanation:
c is the correct answer
Answer:
6=2 , 12=4, 15=5, 24=8
Step-by-step explanation:
