Question

Larger of two numbers is nine less than four times the smaller number if the sum of two numbers is 76 find both numbers

Answer 1

x + y = 76

x = 4y - 9

4y - 9 + y = 76

5y = 65

y = 13

13 + x = 76

x = 63

Answer 2

Answer:

17 and 59

Step-by-step explanation:

Given: Larger of two numbers is nine less than four times the smaller number. The sum of two numbers is 76.

To find: Both the numbers

Solution:

Let the smaller number be x and the larger number be y.

It is given that the sum of the numbers is 76.

So, $x+y=76$

Also, the larger number is 9 less than 4 times the smaller number. So, we have $y=4x-9$

On substituting $y=4x-9$ in $x+y=76$ we get

$x+4x-9=76$

$5x-9=76$

$5x=76+9$

$5x=85$

$x=\frac{85}{5}$

$x=17$

So, the smaller number is 17  

larger number is $4(17)-9=59$

Hence, the smaller number is 17 and the larger number is 59.