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2 years ago

Make a table of values for each equation. Please hurry this is due tonight.

Mathematics

2 answers:

vlada-n [284]2 years ago

4 0

Last ones are the common

astraxan [27]2 years ago

3 0

Answer:

Last two ones in X are 16 and 24

Y goes like this: -8, -5, -2, 1, 4

Step-by-step explanation:

Math

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A scientist used 2 gallons of liquid for every 3 hours he works. He uses __ of a gallon each hour he works.

tiny-mole [99]

He uses 2/3 of a gallon each hour he works.

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2 years ago

PLEASE HELP. <br> I know how to do these but I'm stuck on this one.

Nezavi [6.7K]

Steve ran 11 miles

let the distance Steve ran be x

Then distance Kevin ran is x + 4 ( 4 miles more than Steve )

x + x + 4 = 26 ( the sum of their distance is 26 )

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2x = 22 ( divide both sides by 2 )

x = 11

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3 years ago

Michelle draws a card from a standard deck of 52 cards. She replaces the card and draws a second card. What is the probability t

erma4kov [3.2K]

To draw a heart, one would be choosing 1 card of 13 possible hearts, and 0 from the remaining 39 non-hearts. With respect to the entire deck, one would be choosing 1 card from 52 total cards. So the probability of drawing a heart is

$\dfrac{\dbinom{13}1\cdot\dbinom{39}0}{\dbinom{52}1}=\dfrac{13\cdot1}{52}=\dfrac14$

When Michelle replaces the card, the deck returns the normal, so the probability of drawing any card from a given suit is the same, $\dfrac14$ . In other words, drawing a spade is independent of having drawn the heart first.

So the probability of drawing a heart, replacing it, then drawing a spade is $\dfrac14\cdot\dfrac14=\dfrac1{16}$ .

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3 years ago

Read 2 more answers

According to the histogram of travel times to work from the US 2000 census (Page 6 of "Journey to Work: 2000"), roughly what per

erastovalidia [21]

Histograms are used to represent data, where the length of each bar represents the frequency of the data element

The histogram is not given; So, I will give a general explanation.

Assume that the number of commuters that travel more than 45 minutes is 450, while the total number of commuters surveyed is 500.

The percentage of commuters that travel more than 45 minutes is the quotient of the commuters that travel more than 45 minutes and the total number of surveyed commuters.

So, we have:

$\%Percentage = \frac{450}{500}$

Divide 450 by 500

$\%Percentage = 0.9$

Express as percentage

$\%Percentage = 90\%$

Hence, the percentage of commuters that travel more than 45 minutes is 90%