Answer:
The answer is "After trading, the value would be higher because preferences are diverse".
Step-by-step explanation:
Every person receives a resulting in the possibility from either a grocery shop and gives a value of from 1 to 10. (high). Participants trade these goods with each other for items that prefer to receive randomly but instead assign a second value to the object that finishes after the trade is concluded (1 to 10 again). Its value would've been higher after trading because the total of those before trading choices is unique compared to an exchange sum.
Can u post pictures of the tally chart
Step-by-step explanation:
Claim:
it takes n - 1 number of breaks to break the bar into n separate squares for all integers n.
Basic case -> n = 1
The bar is already completely broken into pieces.
Case -> n ≥ 2
Assuming that assertion is true for all rectangular bars with fewer than n squares. Break the bar into two pieces of size k and n - k where 1 ≤ k < n
The bar with k squares requires k − 1 breaks and the bar with n − k squares
requires n − k − 1 breaks.
So the original bar requires 1 + (k−1) + (n−k−1) breaks.
simplifying yields,
1 + k − 1 + n − k − 1
1 - 1 + n - 1
n - 1
Therefore, we proved as we claimed that it takes n - 1 breaks to break the bar into n separate squares.
Answer: 26xy-5
(x3y6)-2 + (x2y4)-3
(18xy)-2 + (8xy)-3
18xy -2 + 8xy - 3
26xy -5
Step-by-step explanation:
x/5 + 7 = 16
x/5 = 16 - 7
x/5 = 9
x = 9×5
= 45
