All categories

3 years ago

What is 10+10x20 please help

Mathematics

2 answers:

Furkat [3]3 years ago

5 0

210

10+10x20
10+200
210

svp [43]3 years ago

4 0

Use the PEMDAS system
P= Parenthesis
E=Exponents
M=Multiplication
D=Division
A=Addition
S=Subtract

So in 10+10×20
First, multiply 10×20= 200
So now it is 10+200
Then add 10+200 which equals 210

So the answer is 210

You might be interested in

Find the x and the area of the shape perimeter is 64.5

Umnica [9.8K]

Answer:

x=8

A = 192

Step-by-step explanation:

The perimeter is the sum of the outer lengths

17.9 + 22.6 + 3x = 64.5

Combine like terms

40.5 +3x = 64.5

Subtract 40.5 from each side

40.5 +3x -40.5 = 64.5 - 40.5

3x =24

Divide each side by 3

3x/3 = 24/3

x = 8

The area of a triangle is given by

A = 1/2 bh

The base is 3x = 3(8) =24

and the height is 2x = 2(8) =16

A = 1/2 (24) * 16

A =192

4 0

3 years ago

Two skiers are 30 kilometers apart and head towards each other. They meet in 2 hours. If the second skier is 5 kilometers per ho

DENIUS [597]

Answer:

Speed of first skier = 5 km/h

Speed of second skier = 10 km/h

Step-by-step explanation:

Given:

Distance between skiers = 30 km

Time after which they meet = 2 hours

Second skier is 5 km/h faster than the first skier.

To find speed of each skier.

Solution:

Let the speed of first skier be in km/h = $x$

<em>Distance covered in km 2 hours will be = $Speed\times time=x\times 2=2x\ km$ </em>

Speed of second skier in km/h can be given as = $x+5$

<em>Distance traveled by second skier after 2 hours will be = $Speed\times time=(x+5)\times 2=(2x+10)\ km$ [Using distribution]</em>

Since, the skiers were 30 km apart initially, so the total distance covered by both of them when they meet after 2 hours will be = 30 km

Thus, we have:

$2x+2x+10=30$

Solving for $x$

$4x+10=30$

Subtracting both sides by 10.

$4x+10-10=30-10$

$4x=20$

Dividing both sides by 4.

$\frac{4x}{4}=\frac{20}{4}$

$x=5$

Speed of first skier = 5 km/h

Speed of second skier = $5+5$ = 10 km/h

8 0

3 years ago

What is the next term of AP : √2, √8, √18, .......?

solmaris [256]

Answer:

$\sqrt {32}$

Step-by-step explanation:

Next term of the given AP can be obtained by adding common difference (d) in the last term $\sqrt {18}$

$d = \sqrt{18} - \sqrt{8} = 3 \sqrt{2} - 2 \sqrt{2} = \sqrt{2} \\ next \: term = \sqrt{18} + \sqrt{2} \\ = 3 \sqrt{2} + \sqrt{2} \\ = 4 \sqrt{2} \\ = \sqrt{ {4}^{2} \times 2 } \\ = \sqrt{16 \times 2} \\ \huge \red{ \boxed{next \: term = \sqrt{32} }}$

8 0

3 years ago

What is the solution to the trigonometric inequality 2sin(x)+3>sin ^2(x) over the interval

navik [9.2K]

The intervals that satisfy the given trigonometric Inequality are; 0 ≤ x < 3π/2 and 3π/2 < x ≤ 2π

<h3>How to solve trigonometric inequality?</h3>

We are given the trigonometric Inequality;

2 sin(x) + 3 > sin²(x)

Rearranging gives us;

sin²(x) - 2 sin(x) - 3 < 0

Factorizing this gives us;

(sin(x) - 3)(sin(x) + 1) < 0

Thus;

sin(x) - 3 = 0 or sin(x) + 1 = 0

sin(x) = 3 or sin(x) = -1

sin(x) = 3 is not possible because sin(x) ≤ 1.

Thus, we will work with;

sin(x) = -1 for the interval 0 ≤ x ≤ 2π radians.

Then, x = sin⁻¹(-1)

x = 3π/2.

Now, if we split up the solution domain into two intervals, we have;

from 0 ≤ x < 3π/2, at x = 0. Then;

sin²(0) - 2 sin(0) - 3

= 0² - 0 - 3

= -3 < 0

Thus, the interval 0 ≤ x < 3π/2 is true.

From 3π/2 < x ≤ 2π, take x = 2π. Then;

sin²(2π) - 2 sin(2π) - 3

= 0² - 0 - 3

= -3 < 0

Thus, the interval 3π/2 < x ≤ 2π is also true.

Read more about trigonometric inequality at; brainly.com/question/27862380

#SPJ1

3 0

2 years ago

Can someone help me out please!?

Nezavi [6.7K]

48 on call = 3.5 hours for 10 dollars = 1/2 hours for 1.5

6 0

3 years ago