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marta [7]
3 years ago
6

What is the domain of the function y=2.X-6? - 0 O 0 O 3 6

Mathematics
1 answer:
Yuki888 [10]3 years ago
5 0
The domain of this function is the set of real numbers.
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2+3(2+15)
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Given tan θ = 3/4 for acute angle θ, find the value of a and b for the statement cos θ = a/b.
Furkat [3]

Step-by-step explanation:

\tan \theta =  \frac{3}{4}  \\  \\ \sec \theta =  \sqrt{1 +  { \tan }^{2} \theta}  \\  \hspace{22 pt} =  \sqrt{1 +  {( \frac{3}{4}  )}^{2} }  \\  \hspace{22 pt} =  \sqrt{1 +  {\frac{9}{16}  }}  \\ \hspace{22 pt} =  \sqrt{ {\frac{16 + 9}{16}  }}  \\  \hspace{22 pt} =  \sqrt{ {\frac{25}{16}  }}  \\ \red{  \boxed{\bold{ \therefore  \sec \theta  =  { {\frac{5}{4}  }} }}} \\  \\ \cos \theta  = \frac{1}{\sec \theta  }  =  \frac{4}{5}  =  \frac{a}{b}  \\   \\ \implies \: a = 4 \: and \: b = 5

6 0
3 years ago
Simplify this expression: cos theta/ tan theta cot theta
Dmitry_Shevchenko [17]
Q: \frac{cos\theta}{tan\theta.cot\theta}=?

A:

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because... tan\theta.cot\theta=1
*********************************************************
Q: \frac{cos\theta}{tan\theta}.cot\theta=?

A:

\frac{cos\theta}{tan\theta}.cot\theta&= \\  \\ \frac{cos\theta}{\frac{sin\theta}{cos\theta}}.\frac{cos\theta}{sin\theta}&= \\  \\ \frac{cos^2\theta}{sin\theta}}.\frac{cos\theta}{sin\theta}&= \\  \\ \frac{cos^3\theta}{sin^2\theta}}&= cos^3\theta.cosec^2\theta
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4 years ago
5(9-4+3)/2*5<br> What is the answer following order of operations
AleksAgata [21]

Answer:

100

Step-by-step explanation:

9-4+3=8

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40/2=20

20*5=100

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3 years ago
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Answer:

15: A

16: C

Step-by-step explanation:

I have no idea but hopefully I helped you

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3 years ago
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