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1 answer:
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Answer:
The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.
Step-by-step explanation:
let S be the sample space for the inspection of the light bulbs.
Therefore, n(s) = 800
let ' A ' be the event of no defects bulbs.
Therefore, n(A) = 796
Now the Experiment probability for a light bulb chosen has no defects will be given by,
Substituting the values we get
The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.
Source: https://socratic.org/questions/what-is-2000-miles-increased-by-by-33
