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jekas [21]
3 years ago
11

Simplify

\frac{6x^3}{2x^9}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
erik [133]3 years ago
8 0

Answer:

\frac{3}{ {x}^{6} }

Step-by-step explanation:

\frac{6 {x}^{3} }{2x {}^{9} }

Using the division property of power,

\frac{ {x}^{n} }{ {x}^{m} }  = x {}^{n - m}

6 and 2 are the real numbers so just divide 2 by 6.

\frac{6 {x}^{3} }{2 {x}^{9} }  =   \frac{6}{2}  {x}^{3 - 9}

3x {}^{ - 6}

Using the negative properties of power

x {}^{ - n}  =  \frac{1}{x {}^{n} }

Make sure the coefficient in front x, is the numerator.

Since 3 is our coefficient, it will be 3.

\frac{3}{ {x}^{6} }

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What number exceeds 23 by 4 more than twice the amount by which 15 by -3
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Answer:

The required number is 63    

Step-by-step explanation :

Let the number be x

Now As per question , the equation is written as

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Or, x - 23 = 2 × ( 18) + 4

Or , x - 23 = 36 +4

Or,  x - 23 = 40

So, x = 40 + 23

∴    x = 63

Hence the required number is 63      Answer

6 0
3 years ago
This is the new update of the question
anzhelika [568]

Answer:

d

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3 years ago
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Step-by-step explanation:

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