Answer:
The equation of the straight line is x - 2y +6 =0
Step-by-step explanation:
<u>Explanation:</u>-
Given a point ( 2, 4) and slope m = 
The equation of the straight line passing through the point and having slope 'm'
y - y₁ = m ( x - x₁)
y - 4 = ( x - 2)
2( y -4) = ( x-2)
2 y - 8 = x -2
x - 2 y - 2 + 8 =0
x - 2y + 6 =0
The equation of the straight line is x - 2y +6 =0
Answer:
you multiply the quotient times the divisor and your awnser should be the same as the dividend
Step-by-step explanation:
<h2>Answer:</h2><h2>-4</h2><h2 /><h2>Hope this helps!!</h2>
I think that you are mistaking the memory tool for something else
or a math book is trying to make math cute by calling them 'socatoa joe' and 'mr. pi' and such
anyway, SOH, CAH, TOA is the way to remember
Sine=oposite/hypotonuse
Cosine=adjacent/hypotonuse
Tangent=oposite/adjacent
(oposite side=side oposite the angle
adjacent is the side touching the angle that is not they hypotonuse
and of course the hypotonuse is the longest side aka, side oposite right angle)
