All categories

3 years ago

The perimeter of a rectangular rug is 30 yd and its length is 9 yd.find the area of this rug

1 answer:

4 0

<span>perimeter of a rectangular rug is 30 yd

P= L+L+W+W
</span><span>P= 9+9+W+W
P= 18 + 2W
</span><span>18 + 2W = 30
2W = 30-18
</span><span>W= 12/2 = 6

A= L x W
A= 9 x w
</span><span>A= 9 x 6 = 45 yd square</span>

You might be interested in

I need help with no.7

ziro4ka [17]

Answer:

(a) 315°

(b) 3°

Step-by-step explanation:

Bearings are measured clockwise from north. The triangle described is illustrated in the attachment.

The bearing of P from R is 180° different from the bearing of R from P it will be ...

135° +180° = 315° . . . . bearing of P from R

The bearing of Q from R is 48° more than the bearing of P from R, so is ...

315° +48° = 363°, or 3° . . . . bearing of Q from R

The angle QPR has a value that makes the sum of angles in the triangle equal to 180°. It is ...

180° -48° -55° = 77°

The bearing of Q from P is 77° less than the bearing of R from P, so is ...

135° -77° = 58°

As above, the reverse bearing from Q to P is ...

58° +180° = 238° . . . . bearing of P from Q

8 0

3 years ago

Given: f(x)=x^2, g(x)=x+6, h(x)=7<br><br>Find h{g[f(x)]}

arsen [322]

Step-by-step explanation:

$f(x)=x^2,\ g(x)=x+6,\ h(x)=7\\\\h(x)=7\ \text{It's the constant function. Therefore}\ h\{g[f(x)]\}=7$

4 0

4 years ago

Total profit P is the difference between total revenue R and total cost C. Given the following total-revenue and total-cost fu

gavmur [86]

Answer:

The profit function is:

$P(x)=-x^2+1280x-3300$

The maximum value is 406, 300 occurring when x = 640.

Step-by-step explanation:

The revenue function is:

$R(x)=1300x-x^2$

And the cost function is:

$C(x)=3300+20x$

Then the total profit function will be:

$P(x)=R(x)-C(x)=(1300x-x^2)-(3300+20x)=-x^2+1280x-3300$

This is a quadratic function.

Therefore, the maximum value of the total profit will occur at its vertex point.

The vertex of a quadratic is given by:

$\displaystyle \Big(-\frac{b}{2a}, f\Big(-\frac{b}{2a}\Big)\Big)$

In this case, a = -1, b = 1280, and c = -3300.

Then the point at which the maximum profit occurs is at:

$\displaystyle x=-\frac{1280}{2(-1)}=640$

And the maximum profit will be:

$P(640)=-(640)^2+1280(640)-3300=406300$

5 0

3 years ago

Read 2 more answers

LESSON

bagirrra123 [75]

C is the answer hope that helps have a good day

5 0

3 years ago

Yeah thanks if u help I love u no matter what..

skad [1K]

Answer:

please stop all this love comments

Step-by-step explanation:

okk? that will be better

3 0

2 years ago