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Ede4ka [16]
3 years ago
14

What is the average rate of change for f(x) = 2x + 2 over the interval -1 < x <1

Mathematics
2 answers:
MaRussiya [10]3 years ago
8 0

Answer:

the average rate of change for f(x) over the given interval is 2.

Step-by-step explanation:

The function f(x) = 2x + 2 has a straight line graph, and the slope of this line is always 2.  Thus, the average rate of change for f(x) over the given interval is also 2.

Korolek [52]3 years ago
7 0

Answer:

The average rate of change of f(x) over the interval −1 ≤ x ≤ 1 is -1.

Step-by-step explanation:

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Answer:

5/2

Step-by-step explanation:

When you are finding the slope of a parallel line, the other line always has the same slope as the first line but different y intercept.

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Which of these are mathematical laws that help us solve numerical problems? decimals graphs formulas percentages fractions
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Formulas are mathematical laws that help us solve problems.

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Alex wants to arrange chairs in such a way that the number of chairs in a row is equal to the number of columns. He has ordered
PIT_PIT [208]

Answer:

84

59

Step-by-step explanation:

In other to have the same number of chayes in both rows and columns ;

If the Number of chairs per row = x ; then number of chairs per column = x

Then the total number of chairs needed = x * x = x²

Hence, if there are 5100 chairs ;

Number of chairs needed more ;

Take the square root of 5100 ;the round to the next whole number :

B.) For number of chairs to be removed ;

Take the square root of 5100 and round down to the whole number.

Hence,

A.) = √5100 = 71.414 = 72

72² - 5100 = 84

B.) 5100 = 71.414 = 71

5100 - 71² =

8 0
2 years ago
How do I graph y=-6/5x
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3 0
3 years ago
A golfer hits an errant tee shot that lands in the rough. A marker in the center of the fairway is 150 yards from the center of
Gwar [14]

\bold{\huge{\underline{ Solution}}}

<h3><u>Given </u><u>:</u><u>-</u></h3>

  • A marker in the center of the fairway is 150 yards away from the centre of the green
  • While standing on the marker and facing the green, the golfer turns 100° towards his ball
  • Then he peces off 30 yards to his ball

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>distance </u><u>between </u><u>the </u><u>golf </u><u>ball </u><u>and </u><u>the </u><u>center </u><u>of </u><u>the </u><u>green </u><u>.</u>

<h3><u>Let's </u><u> </u><u>Begin </u><u>:</u><u>-</u></h3>

Let assume that the distance between the golf ball and central of green is x

<u>Here</u><u>, </u>

  • Distance between marker and centre of green is 150 yards
  • <u>That </u><u>is</u><u>, </u>Height = 150 yards
  • For facing the green , The golfer turns 100° towards his ball
  • <u>That </u><u>is</u><u>, </u>Angle = 100°
  • The golfer peces off 30 yards to his ball
  • <u>That </u><u>is</u><u>, </u>Base = 30 yards

<u>According </u><u>to </u><u>the </u><u>law </u><u>of </u><u>cosine </u><u>:</u><u>-</u>

\bold{\red{ a^{2} = b^{2} + c^{2} - 2ABcos}}{\bold{\red{\theta}}}

  • Here, a = perpendicular height
  • b = base
  • c = hypotenuse
  • cos theta = Angle of cosine

<u>So</u><u>, </u><u> </u><u>For </u><u>Hypotenuse </u><u>law </u><u>of </u><u>cosine </u><u>will </u><u>be </u><u>:</u><u>-</u>

\sf{ c^{2} = a^{2} + b^{2} - 2ABcos}{\sf{\theta}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ x^{2} = (150)^{2} + (30)^{2} - 2(150)(30)cos}{\sf{100°}}

\sf{ x^{2} = 22500 + 900 - 900cos}{\sf{\times{\dfrac{5π}{9}}}}

\sf{ x^{2} = 22500 + 900 - 900( - 0.174)}

\sf{ x^{2} = 22500 + 900 + 156.6}

\sf{ x^{2} = 23556.6}

\bold{ x = 153.48\: yards }

Hence, The distance between the ball and the center of green is 153.48 or 153.5 yards

5 0
2 years ago
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