-90 = -2(6a – 3) Pls help just solving an equation. :)
1 answer:
Answer:
a=8
Step-by-step explanation:
We are asked to solve this equation -90=-2(6a-3) . As here our variable is a , we will solve it for a. Let us do it step by step
1. Opening the brackets and distribution of -2 inside
-90=-12a+6
2. Subtracting 6 from both sides we get
-90-6=-12a+6-6
-96=-12a
3. Dividing both sides by 12 we get
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Answer:
Pippa
Step-by-step explanation:
A square has
- parallel opposite sides
- perpendicular adjacent sides
- perpendicular diagonals
A rhombus has
- parallel opposite sides
- non-perpendicular adjacent sides
- perpendicular diagonals
Thus, we can identify the shape by comparing the slopes of the adjacent sides.
1. Draw the shape
See the graph below
2. Calculate the slope of AB
m = (y₂ - y₁)/(x₂ - x₁) = (4 - (-1))/(9 - 5) = (4 + 1)/4 = 5/4
3. Calculate the slope of BC
If BC⟂AP, its slope should be -4/5 .
m = (y₂ - y₁)/(x₂ - x₁) = (1 - 4)/(15 - 9) =-3/6 = -1/2
½ ≠ -⅘
The two lines are not perpendicular.
Pippa is right. The shape is a rhombus.
