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wel
4 years ago
10

If one row in an echelon form of an augmented matrix is left bracket Start 1 By 5 Matrix 1st Row 1st Column 0 2nd Column 0 3rd C

olumn 0 4st Column 5 5st Column 0 EndMatrix right bracket 0 0 0 5 0 ​, then the associated linear system is inconsistent.Is this statement true or​ false?
Mathematics
1 answer:
Step2247 [10]4 years ago
8 0

Answer:

Inconsistent - TRUE

Step-by-step explanation:

A system of linear equation is said to be inconsistent if it has no solution. that is from the graph, the lines does not intersect compared to a consistent equations that has solutions and intersect on the graph.

From the written augmented matrix = ( 0)

                                                               ( 0)

                                                               ( 0)

                                                               ( 5)

                                                               ( 0)

from the second row of the matrix, it is evident that it has no solutions hence INCOSISTENT

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3 years ago
Simplify the expression <br><br> -2b - 6 + 3b - 2
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Hello!

To do this we need to combine like terms, meaning combine the terms that have the same variables.

b is one variable that can be combined:

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3 years ago
$85 Restaurant Bill; 15% Tip
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Answer:

97.75

Step-by-step explanation:

15% of 85 is  12.75

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3 years ago
Tennis elbow is thought to be aggravated by the impact experienced when hitting the ball. The article "Forces on the Hand in the
Gnoma [55]

Answer:

Step-by-step explanation:

Hello!

The objective is to study whether there is a greater force after impacting on one- handed backhand drive in advanced tennis players than in intermediate tennis players.

Sample 1: Advanced tennis players

X₁: Force (N) on the hand just after impact on a one- handed backhand drive for an advanced tennis player.

n₁= 6

X[bar]₁= 40.29 N

S₁= 11.29

Sample 2: Intermediate players

X₂: Force (N) on the hand just after impact on a one- handed backhand drive for an intermediate tennis player.

n₂= 8

X[bar]₂= 21.40

S₂= 8.30

Assuming that both variables have a normal distribution and both population variances are equal, to compare these two populations is best to do so trough their population means using a t-test for independent samples.

If the force is greater for the advanced players than for the intermediate players, then you'd expect the population mean for the advanced players to be greater than the population mean for the intermediate players:

H₀: μ₁ ≤ μ₂

H₁: μ₁ > μ₂

α: 0.05

t= \frac{(X_[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ~~t_{n_1+n_2-2}

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{5*127.51+7*68.92}{6+8-2} }= 9.66

t_{H_0}= \frac{(40.29-21.40)-0}{9.66\sqrt{\frac{1}{6} +\frac{1}{8} } } = 3.62

Using the p-value approach, the decision rule is

If p-value ≤ α, reject the null hypothesis

If p-value > α, do not reject the null hypothesis

The p-value for this test is 0.00024, it is less than the level of significance, so the decision is to reject the null hypothesis.

This means that at a 5% significance level you can conclude that the average force experienced on the hand after a one-handed backhand drive for advanced players is greater than the average force experienced on the hand after a one-handed backhand drive for intermediate players.

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3 years ago
Could someone answer these 3 for me?
KengaRu [80]

Answer:

x=4.77

Angle 3=98.32 degrees

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Step-by-step explanation:

(Assuming these are parallel lines), Angle 3 and angle 5 are equal because they are alternate Angles. Therefore we can write the following equation to solves for x:

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Which we can now solve:

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13x=62

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We can then use this x to calculate angle 3:

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Finally,

Angle 6 and angle 3 are interior angles, so they add up to 180 degrees.

So to find angle 6,we can just subtract angle 3 from 180:

180-98.32=81.68 degrees.

Hope this helped!

6 0
3 years ago
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