Ask question

Ask question

All categories

SVETLANKA909090 [29]

3 years ago

12

Y=10/x+5 linear or nonlinear

1 answer:

Volgvan3 years ago

8 0

Answer: Linear

Step-by-step explanation:

The equation y=mx+b which is used for this equation is a linear function.

You might be interested in

Don has an album that holds 900 hockey cards. Each page of the album holds 9 hockey cards. If 68% of the album is empty, how m

nikitadnepr [17]

Since there are 9 hockey cards per page and it holds 900 hockey cards you can multiply 9 by 68 to get the total of 612 hockey cards. Then take 900 and subtract 612 from it and you should get 288 hockey cards in the album. Then divide that number by 9 to get the total number of pages filled 288/9=32 pages filled

3 0

3 years ago

Read 2 more answers

Find the remainder when $3 \times 13 \times 23 \times 33 \times \ldots \times 183 \times 193$ is divided by $5$.

Trava [24]

209.095.543and 8 tenths

5 0

3 years ago

A bag contains 5 2/5kg of sand. The bag has a hole in it. Every 10 minutes, 1 2/3kg of sand escapes from the bag. After 20 minut

fenix001 [56]

Quantify of sand in a bag =

$= \: 5 \frac{2}{5} \ \:$

$= \frac{(5 \times 5 +2) }{5}$

$= \frac{27}{5} \: kg$

Quantity of sand that escapes in every 10 minutes :-

$= 1 \frac{2}{3} kg$

Quantity of sand that will escape in 20 minutes :-

$= 1 \frac{2}{3} \times 2$

$= \frac{(3 \times 1 + 2)}{3} \times 2$

$= \frac{5}{3} \times 2$

$= \frac{10}{3}$

Quantity of sand that will remain in the sand bag :-

$= \frac{27}{5} - \frac{10}{3}$

$= \frac{(27 \times 3)}{15} - \frac{(10 \times 5)}{15}$

$= \frac{81}{15} - \frac{50}{15}$

$= \frac{31}{15}$

$= 2 \frac{1}{5} \: kg$

$therefore \: , \: 2 \frac{1}{5} \: kg \: sand \: is \: left \: in \: the \: bag \: .$

3 0

3 years ago

Which of the following activities are examples of data gathering?

arsen [322]

the correct answer is d

8 0

3 years ago

Simplify without the absolute value |x+3| ; if x>2

inna [77]

Answer:

$x+3$ if $x>2$

Step-by-step explanation:

Recall some following basic ideas about absolute value:

$|0|=0$ or I guess $-(0)=0$

$|3|=3$

$|-3|=-(-3)$ or just $3$ but there is a reason why I wrote it the way I did.

You see that the absolute value returned the same value if the value was positive.

You see that the absolute value returned the opposite value if the value was negative.

You can include 0 in either.

Let's look at $|x+3|$ alone for a second.

* $|x+3|=x+3$ if $x+3$ is positive or zero.

When is $x+3$ positive or zero? [greater than or equal to 0]

$x+3\ge 0$

Subtract 3 on both sides

$x\ge -3$

* $|x+3|=-(x+3)$ if $x+3$ is negative or zero.

When is $x+3$ negative or zero? [less or equal to 0]

$x+3\le 0$

Subtract 3 on both sides

$x\le -3$

So looking at the bullet points (the *), $x>2$ fits into the first inequality.

Therefore, $|x+3|=x+3$ .

8 0

3 years ago