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MArishka [77]
3 years ago
10

PLEASE PLEASE PLEASE HELP

Mathematics
2 answers:
Mandarinka [93]3 years ago
7 0
The formula for slope-intercept form is y = mx + b. Y is the y coordinate, m is the slope, x is the x coordinate, and b is the y intercept. In this example, we have y = -3x + 5. We have the slope and the y intercept. Firstly, we need to plot the y intercept. The y intercept in this example is 5. Therefore, we can have a point at 0, 5. Next, we have the slope. -3 is our slope, which is -3/1. Slope is rise/run. This means that you will need to go down 3 from 0, 5 and to the right by 1. This process can continue for a few more points, and then you can draw your line. Keep in mind, you can also go the other way. For instance, you can go up 3 and left 1.
Cloud [144]3 years ago
6 0
Your rise over run will be -3 over 1 your going to start at the point 5 on the y-axis when your at the point 5 go down 3 then over to the right 1 keep going till it off the graph. Now do the opposite way and go up 3 from 5 and to the left 1 and keep doing that till it’s off the graph.

Hope this helps
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Read 2 more answers
How do I solve: 2 sin (2x) - 2 sin x + 2√3 cos x - √3 = 0
ziro4ka [17]

Answer:

\displaystyle x = \frac{\pi}{3} +k\, \pi or \displaystyle x =- \frac{\pi}{3} +2\,k\, \pi, where k is an integer.

There are three such angles between 0 and 2\pi: \displaystyle \frac{\pi}{3}, \displaystyle \frac{2\, \pi}{3}, and \displaystyle \frac{4\,\pi}{3}.

Step-by-step explanation:

By the double angle identity of sines:

\sin(2\, x) = 2\, \sin x \cdot \cos x.

Rewrite the original equation with this identity:

2\, (2\, \sin x \cdot \cos x) - 2\, \sin x + 2\sqrt{3}\, \cos x - \sqrt{3} = 0.

Note, that 2\, (2\, \sin x \cdot \cos x) and (-2\, \sin x) share the common factor (2\, \sin x). On the other hand, 2\sqrt{3}\, \cos x and (-\sqrt{3}) share the common factor \sqrt[3}. Combine these terms pairwise using the two common factors:

(2\, \sin x) \cdot (2\, \cos x - 1) + \left(\sqrt{3}\right)\, (2\, \cos x - 1) = 0.

Note the new common factor (2\, \cos x - 1). Therefore:

\left(2\, \sin x + \sqrt{3}\right) \cdot (2\, \cos x - 1) = 0.

This equation holds as long as either \left(2\, \sin x + \sqrt{3}\right) or (2\, \cos x - 1) is zero. Let k be an integer. Accordingly:

  • \displaystyle \sin x = -\frac{\sqrt{3}}{2}, which corresponds to \displaystyle x = -\frac{\pi}{3} + 2\, k\, \pi and \displaystyle x = -\frac{2\, \pi}{3} + 2\, k\, \pi.
  • \displaystyle \cos x = \frac{1}{2}, which corresponds to \displaystyle x = \frac{\pi}{3} + 2\, k \, \pi and \displaystyle x = -\frac{\pi}{3} + 2\, k \, \pi.

Any x that fits into at least one of these patterns will satisfy the equation. These pattern can be further combined:

  • \displaystyle x = \frac{\pi}{3} + k \, \pi (from \displaystyle x = -\frac{2\,\pi}{3} + 2\, k\, \pi and \displaystyle x = \frac{\pi}{3} + 2\, k \, \pi, combined,) as well as
  • \displaystyle x =- \frac{\pi}{3} +2\,k\, \pi.
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3 years ago
the container is filled completely with cheese sauce which expression can be used to find the total number of cubic inches of ch
blagie [28]
B is the answer



the formula is :

s = \pi {r}^{2} h
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the diameter is 16
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Answer:

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Step-by-step explanation:

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