Number 1 is B
Number 2 is also B
Answer:
10 losses
Step-by-step explanation:
Here, we want to get the greatest possible number of games the team lost
Let the number of games won be x
Number drawn be y
Number lost be z
Mathematically;
x + y + z = 38
Let’s now work with the points
3(x) + 1(y) + z(0) = 80
3x + y = 80
So we have two equations here;
x + y + z = 80
3x + y = 80
The greatest possible number of games lost will minimize both the number of games won and the number of games drawn
We can have the following possible combinations of draws and wins;
26-2
25-5
24-8
23-11
22-14
21-17
21-17 is the highest possible to give a loss of zero
Subtracting each sum from 38, we have the following loses:
10, 8, 6, 4, 2 and 0
This shows the greatest possible number of games lost is 10
Answer:
I just got off work
Step-by-step explanation:
I just want you know I don’t want you in my car so I’m not trying you mean to you but I’m sorry I’m just gonna go back and get you I know I have a good time to you say you have to talk about me and you don’t want you have ever done that
1.5 divided by 18 is the same as (3/2)/18 = 3/36 this is the same as 1/12.
Answer:
5) 24/5 or 4,4/5 7) 77/8 or 9,5/8
Step-by-step explanation:
You make them "top heavy fractions" and multiply out.